Reputation:
My initializer class
public class HomeServlet extends
AbstractAnnotationConfigDispatcherServletInitializer{
@Override
protected Class<?>[] getRootConfigClasses() {
return null;
}
@Override
protected Class<?>[] getServletConfigClasses() {
return new Class<?>[]{SpringContextConfig1.class};
}
@Override
protected String[] getServletMappings() {
return new String[] {"/home"};
}
}
Configuration Class
@ComponentScan(basePackages={"spittr.controllers"})
@Configuration
@EnableWebMvc
public class SpringContextConfig1 extends WebMvcConfigurerAdapter{
@Bean
public ViewResolver getViewResolver(){
InternalResourceViewResolver ivr=new InternalResourceViewResolver();
ivr.setPrefix("/WEB-INF/jsp/");
ivr.setSuffix(".jsp");
ivr.setExposeContextBeansAsAttributes(true);
return ivr;
}
}
Controller
@Controller
public class HomeController {
@RequestMapping(value="/home",method=RequestMethod.GET)
public String home(){
return "home";
}
}
This is a very simple program, I wrote to test the JavaConfig of Spring MVC.I exactly followed all the steps from "Spring in Action" book.
When I run this code, I'm getting this error
09:41:37,854 ERROR [org.jboss.msc.service.fail] (ServerService Thread Pool -- 72) MSC000001: Failed to start service jboss.undertow.deployment.default-server.default-host./spittr: org.jboss.msc.service.StartException in service jboss.undertow.deployment.default-server.default-host./spittr: java.lang.RuntimeException: java.lang.IllegalArgumentException: Failed to register servlet with name 'dispatcher'.Check if there is another servlet registered under the same name. at org.wildfly.extension.undertow.deployment.UndertowDeploymentService$1.run(UndertowDeploymentService.java:85) at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:511) at java.util.concurrent.FutureTask.run(FutureTask.java:266) at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142) at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617) at java.lang.Thread.run(Thread.java:745) at org.jboss.threads.JBossThread.run(JBossThread.java:320) Caused by: java.lang.RuntimeException: java.lang.IllegalArgumentException: Failed to register servlet with name 'dispatcher'.Check if there is another servlet registered under the same name. at io.undertow.servlet.core.DeploymentManagerImpl.deploy(DeploymentManagerImpl.java:236) at org.wildfly.extension.undertow.deployment.UndertowDeploymentService.startContext(UndertowDeploymentService.java:100) at org.wildfly.extension.undertow.deployment.UndertowDeploymentService$1.run(UndertowDeploymentService.java:82) ... 6 more Caused by: java.lang.IllegalArgumentException: Failed to register servlet with name 'dispatcher'.Check if there is another servlet registered under the same name. at org.springframework.util.Assert.notNull(Assert.java:115) at org.springframework.web.servlet.support.AbstractDispatcherServletInitializer.registerDispatcherServlet(AbstractDispatcherServletInitializer.java:98) at org.springframework.web.servlet.support.AbstractDispatcherServletInitializer.onStartup(AbstractDispatcherServletInitializer.java:71) at org.springframework.web.SpringServletContainerInitializer.onStartup(SpringServletContainerInitializer.java:169) at io.undertow.servlet.core.DeploymentManagerImpl$1.call(DeploymentManagerImpl.java:186) at io.undertow.servlet.core.DeploymentManagerImpl$1.call(DeploymentManagerImpl.java:171) at io.undertow.servlet.core.ServletRequestContextThreadSetupAction$1.call(ServletRequestContextThreadSetupAction.java:42) at io.undertow.servlet.core.ContextClassLoaderSetupAction$1.call(ContextClassLoaderSetupAction.java:43) at io.undertow.servlet.api.LegacyThreadSetupActionWrapper$1.call(LegacyThreadSetupActionWrapper.java:44) at io.undertow.servlet.api.LegacyThreadSetupActionWrapper$1.call(LegacyThreadSetupActionWrapper.java:44) at io.undertow.servlet.api.LegacyThreadSetupActionWrapper$1.call(LegacyThreadSetupActionWrapper.java:44) at io.undertow.servlet.api.LegacyThreadSetupActionWrapper$1.call(LegacyThreadSetupActionWrapper.java:44) at io.undertow.servlet.api.LegacyThreadSetupActionWrapper$1.call(LegacyThreadSetupActionWrapper.java:44) at io.undertow.servlet.core.DeploymentManagerImpl.deploy(DeploymentManagerImpl.java:234)
The hightlight of the error is that " Failed to register servlet with name 'dispatcher'.Check if there is another servlet registered under the same name. at org.wildfly.extension.undertow.deployment.UndertowDeploymentService$1.run(UndertowDeploymentService.java:85) "
Please help me to solve this problem. I using WildFly-10 on eclipse.
Upvotes: 0
Views: 9104
Reputation: 11
you can do a few things to overcome that issue.
Upvotes: 0
Reputation: 86
My friend encountered the same problem. The problem was that the correct package name was not set for the class. AAAAnd clean the project before packaging!!!
Here is the code on GitHub
Upvotes: 0
Reputation: 4878
use the configuration class as follows:
@ComponentScan(basePackages={"spittr.controllers"})
@Configuration
@EnableWebMvc
public class SpringContextConfig1 extends WebMvcConfigurerAdapter{
@Override
public void configureViewResolvers(ViewResolverRegistry registry) {
InternalResourceViewResolver ivr=new InternalResourceViewResolver();
ivr.setPrefix("/WEB-INF/jsp/");
ivr.setSuffix(".jsp");
ivr.setExposeContextBeansAsAttributes(true);
registry.viewResolver(ivr);
}
}
Basically you're extending WebMvcConfigurerAdapter
without inheriting any of its methods (in my 4.3.3 Spring version al least).
since you have a single DispatcherServlet
here, you can add the SpringContextConfig1
class to the root context and leave the servlet context empty: switch the body of the method getServletConfigClasses()
under the getRootConfigClasses()
and vice versa - see A Bit on ApplicationContext
Hierarchies.
Moreover, the DispatcherServlet
mapping is more likely /
instead of /home
:
protected String[] getServletMappings() {
return new String[] {"/"};
}
Upvotes: 0