CODEWITHSUNDEEP
c#.netxmlnamespaces
Marc
Marc

Reputation: 9282

C#: How to remove namespace information from XML elements

How can I remove the "xmlns:..." namespace information from each XML element in C#?

Upvotes: 10

Views: 13691

Answers (3)

Simon
Simon

Reputation: 34830

From here http://simoncropp.com/working-around-xml-namespaces

var xDocument = XDocument.Parse(
@"<root>
    <f:table xmlns:f=""http://www.w3schools.com/furniture"">
        <f:name>African Coffee Table</f:name>
        <f:width>80</f:width>
        <f:length>120</f:length>
    </f:table>
  </root>");

xDocument.StripNamespace();
var tables = xDocument.Descendants("table");

public static class XmlExtensions
{
    public static void StripNamespace(this XDocument document)
    {
        if (document.Root == null)
        {
            return;
        }
        foreach (var element in document.Root.DescendantsAndSelf())
        {
            element.Name = element.Name.LocalName;
            element.ReplaceAttributes(GetAttributes(element));
        }
    }

    static IEnumerable GetAttributes(XElement xElement)
    {
        return xElement.Attributes()
            .Where(x => !x.IsNamespaceDeclaration)
            .Select(x => new XAttribute(x.Name.LocalName, x.Value));
    }
}

Upvotes: 7

NickBeaugi&#233;
NickBeaugi&#233;

Reputation: 730

I had a similar problem (needing to remove a namespace attribute from a particular element, then return the XML as an XmlDocument to BizTalk) but a bizarre solution.

Before loading the XML string into the XmlDocument object, I did a text replacement to remove the offending namespace attribute. It seemed wrong at first as I ended up with XML that could not be parsed by the "XML Visualizer" in Visual Studio. This is what initially put me off this approach.

However, the text could still be loaded into the XmlDocument and I could output it to BizTalk fine.

Note too that earlier, I hit one blind alley when trying to use childNode.Attributes.RemoveAll() to remove the namespace attribute - it just came back again!

Upvotes: 2

annakata
annakata

Reputation: 75794

Zombiesheep's cautionary answer notwithstanding, my solution is to wash the xml with an xslt transform to do this.

wash.xsl:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" indent="no" encoding="UTF-8"/>

  <xsl:template match="/|comment()|processing-instruction()">
    <xsl:copy>
      <xsl:apply-templates/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="*">
    <xsl:element name="{local-name()}">
      <xsl:apply-templates select="@*|node()"/>
    </xsl:element>
  </xsl:template>

  <xsl:template match="@*">
    <xsl:attribute name="{local-name()}">
      <xsl:value-of select="."/>
    </xsl:attribute>
  </xsl:template>

</xsl:stylesheet>

Upvotes: 10

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