CODEWITHSUNDEEP
trigonometrysymbolic-mathmaxima
Rick T
Rick T

Reputation: 3389

Solving equations with maxima

I can solve the equation bellow normally 

sin(b1*(x-c1)) = sin(b2*(x-c2))
b1*(x-c1)      =  b2*(x-c2)
c2             = x-(b1*(x-c1))/b2

for c1 = 0, b1 = 1, b2 = 1.5, x = pi/2

c2 = (x-(b1*(x-c1))/b2) = 0.523598775598299

But when I try and do this in Maxima see below the answer is completely different what am I doing incorrectly? 

kill(all)$
numer:true$
phase1:0; freq1:1; freq2:1.5; x:pi/2; solve(sin(freq1*(x-phase1))=sin(freq2*(x-phase2)),phase2);

Answer I get below Answer I get

Upvotes: 1

Views: 1027

Answers (1)

user4489658
user4489658

Reputation:

solve usually works only for simple equations, try Solver.

Also, pi (variable) is not the same as %pi (constant).

kill(all)$
load(solver)$
numer:true;
f:sin(freq2*(x-phase2))=sin(freq1*(x-phase1));
phase1:0; freq1:1; freq2:1.5; x:%pi/2; a:Solver([f],[phase2]);
rhs(a[1][1]),numer;

Answer: 0.5235987755982978

Your second question:

kill(all);
f:sin(b1*(x-c1)) - sin(b2*(x-c2))=0;
triginverses:all;
solve(f,c2);

Upvotes: 3

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