Reputation: 13
var = 86
print((var < 90) & (var >= 80))
prints True
.
But why do all these print False
?
print(var < 90 & var >= 80)
print(var < 90 & (var >= 80))
print((var < 90) & var >= 80)
print(var < 90 & True)
Upvotes: 1
Views: 754
Reputation: 7579
You should be using the and
operator instead for boolean operations.
Since python supports chaining relational operators (i.e. you can use 0 < var < 100
instead of 0 < var and var < 100
) and processes binary operations (i.e. addition, subtraction, bitwise operations, etc.) before relational operators due to operator precedence, all of the failing cases you posted actually mean something else.
var < 90 & var >= 80
is equivalent to (var < 90 & var) and (90 & var >= 80)
var < 90 & (var>=80)
is equivalent to var < 90 & True
for which look at the 4th case.(var<90) & var>=80
is also similar to the 4th case (this resolves to True & var >= 80
which will then resolve to 0 >= 80
).var < 90 & True
is equivalent to var < (90 & True)
. The implementation of the &
operator is designed to return 0
if either one of the operands is not an integer (which is another one of the biggest pitfalls of dynamic typing), which is why all such similar statements resolve to var < 0
which is false.Upvotes: 4
Reputation: 49330
The bitwise operator &
has higher precedence than the comparison operators, so the 90 & var
is evaluated first, and then a chained comparison takes place.
>>> var = 86
>>> var<90 & var>=80 # var<90, and '90&var' is greater than or equal to 80
False
>>> var<(90 & var)>=80 # same as above
False
>>> (var<90) & (var>=80)
True
Upvotes: 0
Reputation: 40844
It is because of Operator precedence
Take print( var<90 & True)
as an example,
print( var<90 & True)
is equivalent to print( var < (90 & True))
and hence it gives False.
However if you put in parenthesis in the right place, i.e. print( (var<90) & True)
, then it will give True.
Upvotes: 1