CODEWITHSUNDEEP
c++
Joe Walley
Joe Walley

Reputation: 21

Confusion converting decimal to hexadecimal in C++

#include <string>
#include <iostream>

using namespace std;

const string hexConversion = "0123456789ABCDEF";

int main() {
    int dec, remainder, quotient; 
    string hexNum = "";

    //input sequence
    cout << "Enter a decimal number: "; 
    cin >> dec; 
    quotient = dec; 

//conversion
    do {
        remainder = quotient % 16; 
        quotient /= 16; 
        hexNum.insert(0, hexConversion[remainder]); 
    } while (quotient != 0); 

    cout << "Your number in hex is " << hexNum << "."; 

}

I do not have a ton of experience coding, and would appreciate some insight as to what I'm doing wrong with this program! Here is the error being conveyed: invalid conversion from 'char' to 'const char*' [-fpermissive]

Upvotes: 2

Views: 104

Answers (3)

Saurav Sahu
Saurav Sahu

Reputation: 13924

That error is coming because there is no such overloaded version of string::insert which takes int and char as arguments.

You can use this overloaded version:

 string& insert (size_t pos, size_t n, char c);

where n = 1 in your case, as you want to add a character once only.

, or 

iterator insert (iterator p, char c);

where p = hexNum.begin()

Checkout http://www.cplusplus.com/reference/string/string/insert/

Upvotes: 0

R Sahu
R Sahu

Reputation: 206567

If you were thinking of using the following function:

iterator insert( iterator pos, CharT ch );

you need to use:

hexNum.insert(hexNum.begin(), hexConverstion[remainder]);

Upvotes: 1

Oleg Bogdanov
Oleg Bogdanov

Reputation: 1732

You are trying to use one of overloads of std::string::insert but none of them accept int and char:

One of the matching your needs is accepting position, count and symbol, so call hexNum.insert(0, 1, hexConverstion[remainder]);

Upvotes: 2

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