CODEWITHSUNDEEP
javascriptarrays
Wasteland
Wasteland

Reputation: 5379

JavaScript - create a grid of arrays

I've got an array of random numbers 1-10 and would like to create 10 arrays, each of them starting with a number from the random array like so:

const shuffled = [3, 6, 8, 2, 7, 1, 10, 4, 9, 5];

let rGrid = [];

// populate arrays
for (let x of shuffled) {
  rGrid[x-1] = new Array(10);
  rGrid[x-1][0] = x;
}
console.log(rGrid);

So ultimately I would like:

array1: 3,,,,,,,,,,,,
array2: 6,,,,,,,,,,,,
array3: 8,,,,,,,,,,,,
etc.

The code I have places ordered numbers 1-10 as first elements of arrays:

array1: 1,,,,,,,,,,,
array2: 2,,,,,,,,,,,
array3: 3,,,,,,,,,,

Please advise. Here's a code pen: http://codepen.io/wasteland/pen/QdvwJj?editors=1010

Upvotes: 1

Views: 354

Answers (3)

Nina Scholz
Nina Scholz

Reputation: 386570

You could apply a new array for each element of shuffled and set the first element to the actual number.

var shuffled = [3, 6, 8, 2, 7, 1, 10, 4, 9, 5],
    array = shuffled.map(a => {
        var r = new Array(10);
        r[0] = a;
        return r;
    });

console.log(array);
.as-console-wrapper { max-height: 100% !important; top: 0; }

Upvotes: 1

tom10271
tom10271

Reputation: 4649

let rGrid = [], 
    i = 0;
shuffled.forEach(function(each){
    let arr = new Array(10);

    arr[0] = each;

    rGrid.push(arr);
});

Upvotes: 0

Amit Kumar
Amit Kumar

Reputation: 1507

This might help 

   rgrid = [] 
   for x in shuffled
       var temp = []
       temp.push(x)
       for i < shuffled.length-1
         temp.push("")
       rgrid.push(temp)

  console.log(rgrid)

Upvotes: 0

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