CODEWITHSUNDEEP
javascriptarraysgrid
lois v
lois v

Reputation: 21

Array of arrays in Javascript

everyone, I'm stuck. The function isGrid returns true if twoD is an array of arrays in that each row has the same number of columns, it returns false otherwise. I'm think I'm supposed to compare the length of two of the functions but I'm stuck

    function isGrid(twoD) {
        var isMatrix = true;
        while(twoD.length!==isGrid)
             isMatrix= false; 
    }  
        return isMatrix;
    }

Upvotes: 0

Views: 131

Answers (2)

loelsonk
loelsonk

Reputation: 3598

Here is working example. I refactored your code a little bit. Pure javascript, no ES6 helpers.

var example1 = [[1,2], [1,2], [1,2], [1,2], [1,2]],
		example2 = [[2,2], [1,1]],
    example3 = [[1,2,3,4], [1,2,3,4], [1,2,3,4], [1,2,3,4], [1,2,3,4]];
		
function isGrid(twoD) {
  var isMatrix = true;
  var arrayToCompare = twoD[0];

  // We start from second element in Array
  for (i = 1; i < twoD.length; i++) {
    var compareWith = twoD[i];

    for (j = 0; j < arrayToCompare.length; j++) {
      var arrayToCompareElements = arrayToCompare[j];

      //console.log(arrayToCompareElements, compareWith[j]);

      if (arrayToCompareElements !== compareWith[j]) {
        isMatrix = false;
        break;
      }
    }


    arrayToCompare = compareWith;
  }

  return isMatrix;
}

console.log(isGrid(example1));
console.log(isGrid(example2));
console.log(isGrid(example3));

Upvotes: 0

kind user
kind user

Reputation: 41893

You could use Array#every to determine if every nested array of given array has the same length by comparing it to e.g. the first nested array.

var arr1 = [[1,2,3], [1,2,3]],
    arr2 = [[1,2], [1,2,3]];
    
    function check(arr){
      return arr.every(v => v.length == arr[0].length);
    }
    
    console.log(check(arr1));
    console.log(check(arr2));

Upvotes: 4

Related Questions