CODEWITHSUNDEEP
python
Krishna Chaitanya
Krishna Chaitanya

Reputation: 181

skip to next item in dictionary

I have nested for loops, i think this is making things complicated here. Here is the dict i have 

dict1 = {'1': '##', '2': '##'}

I am looping through this dict and here is the code

for key,value in dict1.items():
    ###some code ###
        if ##condition is true move to next key in the for loop which is '2'##
           dict1.next()

I have used dict1.next(). But this is throwing an error "dict' object has no attribute 'next'"

Even tried dict1[key] += 1 and dict1[key] = dict1.setdefault(key, 0) + 1

I understand when skipping to next key in dictionary we have to refer index of key to move on to next item. But no luck with anything and I m not sure using "continue" would fulfil my purpose, because currently I have only one value for each corresponding key ("continue" works if it so), but I want to use this code even if each key had more than one value respectively. Such that "If" condition is true for key 1 and its first corresponding value, the next iteration should be for key 2 and its values respectively.

Sorry for long story

Upvotes: 1

Views: 13332

Answers (1)

omri_saadon
omri_saadon

Reputation: 10631

what's wrong with using continue?

dict1 = {'1': [1,4,7], '2': '##'}

for key in dict1.keys():
    if key == "1":
        continue
    else:
        print key, dict1[key]

>>> '2 ##'

You can have the nexy key with the following:

keys = dict1.keys()
n = len(keys)
for i in range(n):
    thisKey = keys[i]
    if some_condition():
        nextKey = keys[(i + 1) % n]
        nextValue = dict1[nextKey]
        print thisKey, nextValue

You have a list of keys, you iterate over the length of the keys. If your condition is true, you can extract the next key and value.

Upvotes: 3

Related Questions