Reputation: 31
I've two arrays:
var filteredTitles = [String]()
var filteredTypes = [String]()
I filter the first array as a part of using searchbar. The order of the elements might change completely. However, I can't filter the second array the same way I did the first one, because I don't want to take it in to count when searching. But I would like for the second array to be in the same order as the first one. So, to recap. How can I filter an array to match another one by indexes perfectly?
An example:
var filteredArray = ["One", "Two", "Three"]
//Sort the below array to ["1", "2", "3"], the order of the upper array
var toBeFilteredArray = ["2", "1", "3"]
WITHOUT using alphabetical or numerical order, as that won't do in this case.
EDIT: TO Russell: How do I sort the titles like this:
// When there is no text, filteredData is the same as the original data
// When user has entered text into the search box
// Use the filter method to iterate over all items in the data array
// For each item, return true if the item should be included and false if the
// item should NOT be included
searchActive = true
filteredData = searchText.isEmpty ? original : original.filter({(dataString: String) -> Bool in
// If dataItem matches the searchText, return true to include it
return dataString.range(of: searchText, options: .caseInsensitive) != nil
})
Upvotes: 0
Views: 121
Reputation: 5554
don't have two arrays - have a single array of a custom type, containing both variables that you need
Define your struct
struct MyCustomData
{
var dataTitle : String = ""
var dataType : String = ""
}
and then declare it
var dataArray : [MyCustomData] = []
populate it and sort it where required - I have populated in reverse order just so that we can see it being sorted
dataArray.append(MyCustomData(dataTitle: "Third", dataType: "3"))
dataArray.append(MyCustomData(dataTitle: "Second", dataType: "2"))
dataArray.append(MyCustomData(dataTitle: "First", dataType: "1"))
let filteredArray = dataArray.sorted {$0.dataTitle < $1.dataTitle}
for filteredElement in filteredArray
{
print("\(filteredElement.dataTitle), \(filteredElement.dataType)")
}
// or, to print a specific entry
print("\(filteredArray[0].dataTitle), \(filteredArray[0].dataType)")
Upvotes: 4
Reputation: 13999
An example of keeping two separate arrays in sync using zip
:
let titles = ["title1", "title3", "title4", "title2"]
let types = ["typeA", "typeB", "typeC", "typeD"]
let zipped = zip(titles, types)
// prints [("title4", "typeC"), ("title2", "typeD")]
print(zipped.filter { Int(String($0.0.characters.last!))! % 2 == 0 })
You can use map
on the filtered result to get back two separate filtered arrays for the titles and types.
Upvotes: 0