CODEWITHSUNDEEP
arraysswift
NikaE
NikaE

Reputation: 624

Swift 3 filter array of objects with elements of array

array1 = array1.filter{ $0.arrayInsideOfArray1.contains(array2[0]) }

Code above works but I'm trying to check if all the elements of $0.arrayInsideOfArray1 match with all the elements of array2 not just [0]

Example: 

struct User {
    var name: String!
    var age: Int!
    var hasPet: Bool!
    var pets: [String]!
}

var users: [User] = []

users.append(User(name: "testUset", age: 43, hasPet: true, pets: ["cat", "dog", "rabbit"]))
users.append(User(name: "testUset1", age: 36, hasPet: true, pets:["rabbit"]))
users.append(User(name: "testUset2", age: 65, hasPet: true, pets:["Guinea pigs", "Rats"]))

let petArr = ["cat", "dog", "rabbit"]

users = users.filter { $0.pets.contains(petArr[0]) }

What I want is any user that has any pet listed in the petArr!

Upvotes: 27

Views: 77253

Answers (2)

Zapko
Zapko

Reputation: 2461

If elements inside the internal array are Equatable you can just write:

array1 = array1.filter{ $0.arrayInsideOfArray1 == array2 }

If they are not, you can make them, by adopting Equatable protocol and implementing:

func ==(lhs: YourType, rhs: YourType) -> Bool

Upvotes: 4

rmaddy
rmaddy

Reputation: 318955

One approach is to update your filter to see if any value in pets is in the petArr array:

users = users.filter { $0.pets.contains(where: { petArr.contains($0) }) }

The first $0 is from the filter and it represents each User.

The second $0 is from the first contains and it represents each pet within the pets array of the current User.

Upvotes: 67

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