CODEWITHSUNDEEP
javascript
NoobSter
NoobSter

Reputation: 1160

why is .join(" "); not working on variable that points to reversed array?

If I chain it: reverser.split(" ").reverse().split(" "), it works. But, if I split, reverse, then join the variable -- it doesn't perform the join:

var s = "How are you";

function reverser(str){
  var reversed = str.split(" ");
  reversed.reverse();
   reversed.join(" ");
  return reversed;
};

console.log("does not work", reverser(s));

console.log("works", reverser(s).join(" "));

Upvotes: 1

Views: 1664

Answers (3)

Anuran Barman
Anuran Barman

Reputation: 1676

split() splits the string into array of strings. You need to store the resulting output everytime so that next operation can be performed right.

var s = "How are you";
function reverser(str){
var reverser = str.split(" ");
var revArray=reverser.reverse();
var revArrayJoined=revArray.join(" ");
return revArrayJoined;
};

console.log(reverser(s));
//output: you are How

Upvotes: 1

Sagar V
Sagar V

Reputation: 12478

joins returns a string and you have to store it in the variable.

var s = "How are you";

function reverser(str){
  var reversed = str.split(" ");
  reversed.reverse();
   reversed=reversed.join(" ");
  return reversed;
};

console.log('doesn\'t work ', reverser(s));

Upvotes: 2

Pointy
Pointy

Reputation: 413757

The .join() function returns a string. It doesn't transform the target array into a string.

So,

reverser = reverser.join(" ");

Upvotes: 2

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