my url pattern throwing an error

Question

my url pattern is www.example.com/[any digit or number] say www.eaxmple.com/slug

my urls.py is:

 url(r'^(?P<[a-z0-9>+)/$', mymethod),

But is saying:- bad character in group name

another query is that i want to process the slug coming with the url. Based on that value i will render different template. Is it possible? How?

Answer 1

I don't know python, so can't say what the url function does, but your regex should probably look like this:

url(r'^(?P<someName>[a-z0-9]+)/$', mymethod)

This will capture the the [a-z0-9] Group of characters under the name "someName".

BTW: What about upper case characters?