CODEWITHSUNDEEP
javascript
JpG
JpG

Reputation: 932

how to replace words in string using javascript?

i have a string,

mystr = 'public\uploads\file-1490095922739.jpg';

i want to replace

public\uploads

with " ", so that i just want to extract only file name ie

file-1490095922739.jpg

or like,

\uploads\file-1490095922739.jpg

how can i do this, is there any methods for this in js or can we do it by replace method.

i am performing the following steps,

var imagepath1;
var imagepath = 'public\uploads\file-1490095922739.jpg';
unwantedChar = 'public|uploads';
regExp = new RegExp(unwantedChar , 'gi');
imagepath = imagepath.replace(regExp , '');
imagepath1 = imagepath;
$scope.model.imagepath = imagepath1.replace(/\\/g, "");

please suggest me optimized method.

Upvotes: 0

Views: 102

Answers (5)

DDT
DDT

Reputation: 414

var url = '/anysource/anypath/myfilename.gif';
var filename = url.slice(url.lastIndexOf('/')+1,url.length);

Search for the last forward slash, and slice the string (+1 because you don't want the slash), with the length of the string to get the filename. This way, you don't have to worry about the path is at all times.

Upvotes: 0

Dax
Dax

Reputation: 203

var input = "public\\uploads\\file-1490095922739.jpg";
var result = input.replace("public\\uploads\\", "");

This is what you're looking for, no need for fancy regexs :). More information about replace can be found here.

Upvotes: 1

DibsyJr
DibsyJr

Reputation: 874

What about just doing:

var imagepath = 'public\\uploads\\file-1490095922739.jpg';
$scope.model.imagepath = imagepath.replace('public\\uploads\\', '');

instead of using a bunch of unnecessary variables?

This way you're getting the file path, removing public\uploads\ and then setting the file path to $scope.model.imagepath

Note that this will only work if the image file path always matches 'public\uploads\*FILENAME*'.

Upvotes: 0

x-ray
x-ray

Reputation: 3329

If you want to get the part of the string after the last backslash character, you can use this:

var filename = mystr.substr(mystr.lastIndexOf('\\') + 1);

Also note that you need to escape the backslash characters in your test string:

var mystr = 'public\\uploads\\file-1490095922739.jpg';

Upvotes: 0

itamar
itamar

Reputation: 3967

Maybe I don't understand the issue - but wouldn't this work?

var mystr = 'public\uploads\file-1490095922739.jpg';
var filename = mystr.replace('public\uploads', '');

Upvotes: 0

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