CODEWITHSUNDEEP
iosswift3
spectre_d2
spectre_d2

Reputation: 203

Take character from a specific position to last (swift 3)

I have some string like "Md. Monir-Uz-Zaman Monir", "Md. Monir-Uz-Zaman Monir01", "Md. Monir-Uz-Zaman Monir876" .... Now I want to take a substring from 20th position character to last. Actually I want output like "Monir","Monir01", "Monir876"... The full string is not fixed but 1st 19 character is fixed.

I have done it in swift 2. But what would be answer for swift 3.

let nameString = str.substringWithRange(Range<String.Index>(start: str.startIndex.advancedBy(19), end: str.endIndex.advancedBy(0)))

Upvotes: 1

Views: 111

Answers (3)

Benzi
Benzi

Reputation: 2459

// swift 3
let input = "Md. Monir-Uz-Zaman Monir"
let start = input.index(input.startIndex, offsetBy: 19)
let required = input[start..<input.endIndex] // "Monir

Upvotes: 1

Nirav D
Nirav D

Reputation: 72440

Use map(_:) with array and then simply use substring(from:) with shorthand argument.

let strArray = ["Md. Monir-Uz-Zaman Monir", "Md. Monir-Uz-Zaman Monir01", "Md. Monir-Uz-Zaman Monir876"]
let nameArray = strArray.map { $0.substring(from: $0.index($0.startIndex, offsetBy: 19)) }
print(nameArray) //["Monir", "Monir01", "Monir876"]

Upvotes: 2

kb920
kb920

Reputation: 3089

Convert string to array and get last object. Try below code

  let string : String = "Md. Monir-Uz-Zaman Monir"
  let fullNameArr = string.characters.split{$0 == " "}.map(String.init)
  print(fullNameArr[fullNameArr.count-1])

Upvotes: 1

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