CODEWITHSUNDEEP
python-3.xfile-io
ocean.1234
ocean.1234

Reputation: 127

Python-Is it possible to index values in a specific line of a file?

I've opened a file for reading and got all the lines printed out.

6,78,84,78,100

146,90,100,90,90

149,91,134,95,80

641,79,115,70,111

643,100,120,100,90

I need to grab the first number in each line to create a dictionary key. The rest of the numbers are the values for the dictionary. Is there a way to use indexing with a for loop to grab each thing from the line?

I've tried using readlines() but that has gotten overly complicated in other ways that I won't go into detail. I would prefer to keep the lines as is and iterate over them if possible.

I tried:

fo=open('tester.csv','r')
def search(fo):
    for line in fo:
        key=line[0]
        value= (line[1],line[2],line[3],line[4])

I want my final output to be a dictionary= {6: (78,84,78,100)}

Upvotes: 1

Views: 2292

Answers (2)

E.T.
E.T.

Reputation: 634

t = open("tester.csv", "r")
tstuff = t.readlines()
outdict = {}
tstufflength = len(tstuff)
for i in tstuff:
    thing1, thing2 = i.split(",", 1)
    realthing2 = thing2.strip("\n")
    outdict[thing1]=realthing2
print(outdict)

Will only work if the lines are all on, well, different lines.

OUTPUT:

{'6': '78,84,78,100', '149': '91,134,95,80', '643': '100,120,100,90', '146': '90,100,90,90', '641': '79,115,70,111'}

Upvotes: 1

RPT
RPT

Reputation: 748

Are you trying to get an output like this?

OUTPUT:

['6', '1', '1', '6', '6']

Then,

f = open('data.csv')
result = []
for line in f:
    if line != '\n':
        result.append(line[0])

print(result)

Upvotes: 1

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