Reputation: 41
I want to open a file, and simply return the contents of said file with each line beginning with the line number.
So hypothetically if the contents of a
is
a
b
c
I would like the result to be
1: a
2: b
3: c
Im kind of stuck, tried enumerating but it doesn't give me the desired format.
Is for Uni, but only a practice test.
A couple bits of trial code to prove I have no idea what I'm doing / where to start
def print_numbered_lines(filename):
"""returns the infile data with a line number infront of the contents"""
in_file = open(filename, 'r').readlines()
list_1 = []
for line in in_file:
for item in line:
item.index(item)
list_1.append(item)
return list_1
def print_numbered_lines(filename):
"""returns the infile data with a line number infront of the contents"""
in_file = open(filename, 'r').readlines()
result = []
for i in in_file:
result.append(enumerate(i))
return result
Upvotes: 1
Views: 17091
Reputation: 1
the simple way to do it: 1st:with open the file -----2ed:using count mechanism: for example:
data = object of file.read()
lines = data.split("\n")
count =0
for line in lines:
print("line "+str(count)+">"+str()+line)
count+=1
Upvotes: 0
Reputation: 53744
A file handle can be treated as an iterable.
with open('tree_game2.txt') as f:
for i, line in enumerate(f):
print ("{0}: {1}".format(i+1,line))
Upvotes: 8
Reputation: 10799
What about using an OrderedDict
from collections import OrderedDict
c = OrderedDict()
n = 1
with open('file.txt', 'r') as f:
for line in f:
c.update({n:line})
#if you just want to print it, skip the dict part and just do:
print n,line
n += 1
Then you can print it out with:
for n,line in c.iteritems(): #.items() if Python3
print k,line
Upvotes: 0
Reputation: 5533
There seems no need to write a python script, awk
would solve your problem.
awk '{print NR": "$1}' your_file > new_file
Upvotes: 1