Reputation: 2826
I am trying to prove the following using the Mathematical Components library:
Lemma bigsum_aux (i: 'I_q) (j: 'I_q) (F G : 'I_q -> R):
(forall i0, F i0 <= G i0) /\ (exists j0, F j0 < G j0) ->
\sum_(i < q) F i < \sum_(i < q) G i.
Initially, I was trying to find some Lemma equivalent to bigsum_aux
in the documentation of ssralg
or bigop
, but I couldn't find any; so this is what I have been able to do so far:
Proof.
move => [Hall Hex]. rewrite ltr_neqAle ler_sum; last first.
- move => ? _. exact: Hall.
- rewrite andbT. (* A: What now? *)
Any help or pointers towards relevant lemmas would be welcome.
Upvotes: 1
Views: 93
Reputation: 6852
You want to split the sum in the "bad" (<) part, then the rest is trivial:
From mathcomp Require Import all_ssreflect all_algebra.
Set Implicit Arguments.
Unset Strict Implicit.
Unset Printing Implicit Defensive.
Open Scope ring_scope.
Import Num.Theory.
Lemma bigsum_aux (R : numDomainType) q (i: 'I_q) (j: 'I_q) (F G : 'I_q -> R)
(hle : forall i0, F i0 <= G i0) z (hlt : F z < G z) :
\sum_(i < q) F i < \sum_(i < q) G i.
Proof.
by rewrite [\sum__ F _](bigD1 z) ?[\sum__ G _](bigD1 z) ?ltr_le_add ?ler_sum.
Qed.
Upvotes: 2