CODEWITHSUNDEEP
pythonlist
user2916886
user2916886

Reputation: 845

printing an increasing number along with the items of a list in python

I have a list in python - ['item1','item2','item3','item4']. I am trying to print this list in following way - 1. ITEMS: item1 2. ITEMS: item2 3. ITEMS: item3 4. ITEMS: item4. I wrote this code but this is giving error as I am trying to specify range() in wrong way:

list_semi = ["%d. ITEMS: %s" % (x for x in range(1,len(bookings)),items) for items in bookings]
print('Your items are {}.'.format(','.join(list_semi)))

bookings in the above code is the list whose sample data I have posted above. How can I print the list in the desired way as I have mentioned above?

UPDATE CASE 2 If my sample input list changes to - [[item1,price1],[item2,price2]...] and I want the sample output as 1. ITEMS: item1, PRICE: price1 2. ITEMS: item2, PRICE: price2 3. ITEMS: item3, PRICE: price3 4. ITEMS: item4, PRICE: price4 then how should I frame my code? the list name is same as bookings

Upvotes: 1

Views: 989

Answers (1)

Moses Koledoye
Moses Koledoye

Reputation: 78546

No need to use range. Iterate on the list object directly, using enumerate to generate the indices. Specify the start parameter as 1:

>>> ' '.join(['{}. ITEMS: {}'.format(i, x) for i, x in enumerate(lst, 1)])
'1. ITEMS: item1 2. ITEMS: item2 3. ITEMS: item3 4. ITEMS: item4'

Update:

>>> lst = [['item1','price1'],['item2','price2']]
>>> ' '.join(['{}. ITEMS: {}, PRICE: {}'.format(i, *x) for i, x in enumerate(lst, 1)])
'1. ITEMS: item1, PRICE: price1 2. ITEMS: item2, PRICE: price2'

Upvotes: 4

Related Questions