CODEWITHSUNDEEP
pythonlistline
sichuanmcl
sichuanmcl

Reputation: 11

Print x number of list and then insert new line in python

I have a list of integer like this

[1, 2, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1]

I want to print maybe 10 int in one line, and then insert a new line so the output should looks like this:

[1, 2, 1, 2, 1, 1, 1, 1, 1, 1,

1, 1, 1, 1, 1, 1, 1, 2, 2, 1,

1, 1, 1, 1, 1, 1, 2, 1, 1, 1,

1, 1, 1, 1, 1, 1, 1, 1, 1, 1,

1, 1, 1, 1, 1, 1, 1, 1, 1, 1]

I need to do this because i need to screenshoot the output of the list to my paper, its better if the list look more tidy. Thanks before.

Upvotes: 0

Views: 626

Answers (6)

BeaverDono
BeaverDono

Reputation: 11

So I was toying around with the yesterday but I had to go to work before I could finished it up. The size variable lets you change the length and it prints it out nicely on the output. If you do need to add brackets to the output that should be easy enough.

Hopefully this points you in the right direction! 👍

myList = ["a", "b", "c", "d", "e", "f", "g", "h", "i"]
size = 5  # Number Per Row
startIndex = 0 # Start at the beginning index of myList

try:
    for x in range(len(myList)):
        for y in range(size):
            if startIndex >= len(myList):
                break
            print(myList[startIndex], end=" ")
            startIndex = startIndex + 1
        print()
        if startIndex >= len(myList):
            break
except IndexError:
    print("\nIndex Error")  # Left this in for debugging purposes

Upvotes: 1

Nothing special
Nothing special

Reputation: 415

I would like to add another answer. It is more pythonic and one-line code.

a, x = list(range(10,77)), 5
print('[', *[str(i)+',' if (j+1)%x!=0 else str(i)+',\n' for j, i in enumerate(a[:-1])],sep='',end=str(a[-1])+']')

Output:

[10,11,12,13,14,
15,16,17,18,19,
20,21,22,23,24,
25,26,27,28,29,
30,31,32,33,34,
35,36,37,38,39,
40,41,42,43,44,
45,46,47,48,49,
50,51,52,53,54,
55,56,57,58,59,
60,61,62,63,64,
65,66,67,68,69,
70,71,72,73,74,
75,76]

Upvotes: 0

Nothing special
Nothing special

Reputation: 415

Try this. I have rigorously tested this one.

n = [1, 2, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1]

i = 0

j = len(n)

j = j - j%10

if len(n)%10==0:
    j -= 10

print(end='[')

while i<j:
    print(*n[i:i+10], sep=',', end=',\n')
    i += 10

print(*n[i:], sep=',', end=']')

Output:

[1,2,1,2,1,1,1,1,1,1,
1,1,1,1,1,1,1,2,2,1,
1,1,1,1,1,1,2,1,1,1,
1,1,1,1,1,1,1,1,1,1,
1,1,1,1,1,1,1,1,1,1,
1,1,1,1,1,1,1,1,1,1,
1,1,1,1,1,1,1]

The example given has 67 elements. My output contains 7 lines. First 6 lines with 10 elements each & the last one with 7 elements. You can replace 10 by any number you want.

Upvotes: 0

Sup
Sup

Reputation: 331

If you dont want to use any external library, here's one way:

print('['+'\n'.join([','.join(map(str, a[i:i+x])) for i in range(0,len(a),x)])+']')

Upvotes: 0

IoaTzimas
IoaTzimas

Reputation: 10624

If you don't want to use a library, here is one way to do it:

for i in range(len(l)//10+1):
    if i==0:
        k=str(l[i*10:i*10+10])
        k=k[:-1]+','
        print(k)
    elif i==len(l)//10:
        k=str(l[i*10:i*10+10])
        k=k[1:-1]+']'
        print(k)
    else:
        k=str(l[i*10:i*10+10])
        k=k[1:-1]+','
        print(k)

Output:

[1, 2, 1, 2, 1, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1, 2, 2, 1,
1, 1, 1, 1, 1, 1, 2, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 1, 1, 1, 1, 1, 1]

Upvotes: 0

alfinkel24
alfinkel24

Reputation: 551

Try pprint.

import pprint
foo = [1, 2, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
pp = pprint.PrettyPrinter(width=30, compact=True)
pp.pprint(foo)

Results in:

[1, 2, 1, 2, 1, 1, 1, 1, 1, 1,
 1, 1, 1, 1, 1, 1, 1, 2, 2, 1,
 1, 1, 1, 1, 1, 1, 2, 1, 1, 1,
 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
 1, 1, 1, 1, 1, 1, 1, 1, 1, 1,
 1, 1, 1, 1, 1, 1, 1]

You can play around with the width and indenting, etc...

Upvotes: 0

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