CODEWITHSUNDEEP
python
Oskar Ingemansson
Oskar Ingemansson

Reputation: 17

Python, find a specific character in a string in a list

If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".

def loopy(items):
    for item in items:
        if item[0] == "a":
            continue
        else:
            print(items)

Upvotes: 0

Views: 2007

Answers (3)

Dadep
Dadep

Reputation: 2788

with few correction :

>>> l=['abi', 'crei', 'fci', 'anfe']
>>> def loopy(list):
...     for i in list:
...             if i[0]=='a':
...                     continue
...             else:
...                     print i
... 
>>> loopy(l)
crei
fci

that you can make shorter this way : 

>>> def loopy(list):
...     for i in list: 
...             if i[0]!='a':
...                     print i
... 
>>> loopy(l)
crei
fci

or to print in one line :

>>> def loopy3(list):
...     for i in list:
...             print i if i[0]!='a' else '',
... 
>>> loopy3(l)
 crei fci

but you can also use a list comprehension as suggest by bogdanciobanu :

>>> def loopy2(list):
...     print [i for i in list if i[0]!='a']
>>> loopy2(l)
['crei', 'fci']

Upvotes: 0

cs95
cs95

Reputation: 403040

How about a filter?

In [191]: print('\n'.join(filter(lambda x: x[0] != 'a', ["abc", "xyz", "test"])))
xyz
test

Upvotes: 1

AGN Gazer
AGN Gazer

Reputation: 8388

def loopy(items):
    for item in items:
        if not item.startswith('a'):
            print(item)

Upvotes: 0

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