Reputation: 81
I have a given list of string and a list of characters and I want to check the string with containing a specific character. Here is an example:
Dictionary = ["Hello", "Hi"]
Character = ['e','i']
it must return a "Hello" else empty list
I am comparing a list of characters with a list of strings but it is giving me a type error.
Dictionary = ["Hello", "Hi"]
Character = ['e']
emptystring = ""
def findwords(dictionary,character):
for i in dictionary,character:
for j in dictionary:
if character[i] == dictionary[i][j]:
return dictionary[i]
else:
j+=1
i+=1
return emptystring
k = findwords(Dictionary,Character)
k
TypeError Traceback (most recent call last)
<ipython-input-49-996912330841> in <module>
----> 1 k = findwords(Dictionary,Character)
2 k
<ipython-input-48-9e9498ec1a51> in findwords(dictionary, character)
5 for i in dictionary,character:
6 for j in dictionary:
----> 7 if str(character[i]) == str(dictionary[i][j]):
8 return str(dictionary[i])
9 else:
TypeError: list indices must be integers or slices, not list
Upvotes: 1
Views: 5319
Reputation: 747
This might clean up your code a bit, I think it is what you are going for...
Dictionary = ["Hello", "Hi"]
Character = ["e"]
def findwords(dictionary, character):
for i in dictionary:
if any(j in i for j in character):
return i
return ""
For all matches:
def findwords(dictionary, character):
matches = []
for i in dictionary:
if any(j in i for j in character):
matches.append(i)
if matches:
return ",".join(matches)
else:
return ""
It will see if anything in the substring matches your word. If it does, return the word, else ""
findwords(["Hello", "Hi"],["e"])
'Hello'
findwords(["Hello", "Hi"],["k"])
''
For your issue:
TypeError: list indices must be integers or slices, not list
for i in dictionary,character: <-- I will be list ['Hello', 'Hi']
for j in dictionary:
if character[i] == dictionary[i][j]: <---- you can't do character[i] where i is ['Hello', 'Hi']
Upvotes: 1
Reputation: 1336
Check this.
Dictionary = ["Hello", "Hi"]
Character = ['e']
def findwords(dictionary,character):
tmp = ""
for i in dictionary:
#convert string to char list
str_arr = list(i)
for j in character:
#if char is in char list then save it in tmp variable
#if you want multiple values then use array instead of tmp
if j in str_arr:
tmp = i
return tmp
k = findwords(Dictionary,Character)
print(k)
Upvotes: 1