CODEWITHSUNDEEP
php
Wyatt
Wyatt

Reputation: 495

Php dynamically replace placeholder variables in string

I want to dynamically replace placeholder variables in a string.

str_replace("\$", $data["Whatever follows the \$], $variable);

\$ signifies a placeholder variable, \$ID for example.

The data I want it to be replace with is in an array. $\ID should be replaced with $data['ID'].

For example, if I have a string that says "The ID is \$ID and name is \$name". I want to replace both the \$ID and \$name with the relevant data in my $data object. $\ID would be $data['ID'] and so on.

This needs to be dynamic. I don't want to hard code it to replace \$ID with $data['ID']. The key used to get the data in $data should be equal to what follows the \$.

I'm having trouble figuring out not only how to do this dynamically like I have talked about, but to do it for every \$ in a string.

Upvotes: 0

Views: 2263

Answers (3)

delboy1978uk
delboy1978uk

Reputation: 12375

This will do the job for you! https://3v4l.org/XRQii

<?php

$string = 'The ID is \$ID and name is \$name';
$row = [
  'ID'=> 5,
  'name' => 'delboy1978uk',
];


function replaceStuff($string, $row) {
    preg_match_all('#\\$\w+#', $string, $matches);
    foreach ($matches[0] as $match) {
        $key = str_replace('$', '', $match);
        $replace = '\\'.$match;
        $string = str_replace($replace, $row[$key], $string);
    }
    return $string;
}

echo replaceStuff($string, $row);

See http://php.net/manual/en/function.preg-match-all.php for more info on preg_match_all().

Upvotes: 0

katona.abel
katona.abel

Reputation: 771

Try this:

$string = 'some $ID $PARAM string';
$values = array("ID" => "idparam", "PARAM" => "p");

preg_match_all("/\\\$(?<name>[a-zA-Z0-9]+)/", $string, $matches);

foreach($matches["name"] as $m) {
    if(!isset($values[$m])) {
        //TODO handling
        continue;
    }
    $string = str_replace('$'.$m, $values[$m], $string);
}

var_dump($string);

The keys in $values should be name of the parameter without the dollar sign.

Upvotes: 0

Gergely Lukacsy
Gergely Lukacsy

Reputation: 3074

Use printf() or sprintf().

If you mark your placeholder with a number, you can repeat it any number of times in your string.

sprintf("This is my test string. Here's a placeholder: %1$s, and a another: %2$s, First one again: %1$s", $var1, $var2);

Upvotes: 1

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