CODEWITHSUNDEEP
php
Alica Kindel
Alica Kindel

Reputation: 183

how to replace a placeholder in a string?

Not very sure how to word this question but I'll give an example.

$string = 'Hey, $name. How are you?';

When I post this string, $name doesn't change. How can I make it so I can put something like +name+ so it changes to the name. I've tried seaching for it but I don't know what to search for so I don't have any luck. It's probably really simple but i'm just blanking out. Thanks

Upvotes: 17

Views: 33437

Answers (5)

usilo
usilo

Reputation: 365

Another way to achieve this is to use msgfmt_format_message

You must have the intl extension enabled. Profile of the method is:

msgfmt_format_message(string $locale, string $pattern, array $values): string|false`

For example:

$name = "Alica";
$string = msgfmt_format_message('en_US', 'Hey, {0}. How are you?', array($name));

Would return: Hey, Alica. How are you?

Upvotes: 0

Nick
Nick

Reputation: 2911

I've always been a fan of strtr.

$ php -r 'echo strtr("Hi @name. The weather is @weather.", ["@name" => "Nick", "@weather" => "Sunny"]);'
Hi Nick. The weather is Sunny.

The other advantage to this is you can define different placeholder prefix types. This is how Drupal does it; @ indicates a string to be escaped as safe to output to a web page (to avoid injection attacks). The format_string command loops over your parameters (such as @name and @weather) and if the first character is an @, then it uses check_plain on the value.

Upvotes: 23

Brad Christie
Brad Christie

Reputation: 101614

You can use place-holders and str_replace. Or use PHP's built-in sprintf and use %s. (And as of v4.0.6 you can swap the ordering of arguments if you'd like).

$name = 'Alica';

// sprintf method:
$format = 'Hello, %s!';
echo sprintf($format, $name); // Hello, Alica!

// replace method:
$format = "Hello, {NAME}!";
echo str_replace("{NAME}", $name, $format);

And, for anyone wondering, I understood that is trouble templating a string, not PHP's integrated concatenation/parsing. I just assume keep this answer up though as I'm still not 100% sure this OP's intent

Upvotes: 31

Josh
Josh

Reputation: 12566

A third solution, no better or worse than the aforementioned, is concatenation:

echo 'Hello '. $name .'!!!';

Upvotes: 2

user142162
user142162

Reputation:

You should be wrapping the string in double quotes (") if you want variables to be expanded:

$name = "Alica";
$string = "Hey, $name. How are you?"; // Hey, Alica. How are you?

See the documentation.

Upvotes: 11

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