CODEWITHSUNDEEP
pythonpython-2.7datetime
Justin S
Justin S

Reputation: 1459

TypeError: can't compare datetime.datetime to datetime.time

I'm trying to parse a string which has a military time hour value

'10:00:00'

I am able to do this with

>>> datetime.datetime.strptime('10:00:00', '%H:%M:%S').time()
datetime.time(10, 0)

Then I get the current time in a specific time zone:

>>> datetime.datetime.utcnow()+ datetime.timedelta(hours=10)
datetime.datetime(2017, 8, 3, 11, 26, 1, 909000)

What I'm trying to do is compare the time from the string with the current time in utc. But when I compare the values

>>> bne_time_now > tag_time
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: can't compare datetime.datetime to datetime.time

What I think I need to do is set a default time value when I parse the string but I am not sure how to do this?

Upvotes: 0

Views: 8638

Answers (2)

Justin S
Justin S

Reputation: 1459

So I managed to get this working:

>>> today = datetime.datetime.utcnow()
>>> today
datetime.datetime(2017, 8, 3, 1, 52, 33, 253000)
>>> datetime.datetime.strptime('10:00:00', '%H:%M:%S').replace(year=today.year, month=today.month, day=today.day)
datetime.datetime(2017, 8, 3, 10, 0)

just posting here in case someone else needs this solution

Upvotes: 0

Zachary King
Zachary King

Reputation: 13

Convert your datetime.datetime object to a datetime.time object using the time() method.

>>> (datetime.datetime.utcnow() + datetime.timedelta(hours=10)).time()
datetime.time(11, 33, 51, 523382)

Then you can compare the two time objects.

Upvotes: 1

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