CODEWITHSUNDEEP
pythonstringdigit
Reggie Sausse
Reggie Sausse

Reputation: 11

Python treats + as a digit?

Basically im making a small piece of code to remove the end character of a string until the string passes .isdigit.

def string_conversion(string):
    for i in string:
        if i.isdigit == False:
            string = string[0:len[string]-1]
            print(string) #This is just here to see if it goes through
test = "60+" 
string_conversion(test)

I used http://www.pythontutor.com/visualize.html to see why I wasn't getting any output, it passed a + symbol as a digit, just like the numbers 6 and 0.

Am I doing something wrong or does python treat + as a digit?

Upvotes: 0

Views: 80

Answers (2)

MSeifert
MSeifert

Reputation: 152765

str.isdigit is a method not an attribute, so (as was already mentioned in the comments) you need to call it.

Also you check each character (starting from the left side) for isdigit but if it's not passing the isdigit() test you remove a character from the right side. That doesn't seem right. You probably wanted to iterate over the for i in reversed(string) (or using slicing: for i in string[::-1]).

But you also could simplify the logic by using a while loop:

def string_conversion(string):
    while string and not string.isdigit():
        string = string[:-1]
    return string

Upvotes: 2

MegaBytes
MegaBytes

Reputation: 6385

def string_conversion(string):
    for i, s in enumerate(string):
        if s.isdigit() == False:
            string = string[:i]
            break
    print(string) #This is just here to see if it goes through

test = "60+"
string_conversion(test)

Try This

Upvotes: 1

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