CODEWITHSUNDEEP
cudacaffe
John
John

Reputation: 3070

How to fix error calling a __host__ function("std::max<double> ") is not allowed in CUDA?

#include <algorithm>
#include <vector>
template <typename Dtype>
    __global__ void R_D_CUT(const int n, Dtype* r, Dtype* d
        , Dtype cur_r_max, Dtype cur_r_min, Dtype cur_d_max, Dtype cur_d_min) {
        CUDA_KERNEL_LOOP(index, n) {
            r[index] = __min(cur_r_max, __max(r[index], cur_r_min));
            d[index] = __min(cur_d_max, __max(d[index], cur_d_min));
        }
    }

In above code, it can work well in Window. However, it does not work in Ubuntu due to __min and __max function. To fix it by replace __min to std::min<Dtype> and max to std::max<Dtype>:

template <typename Dtype>
    __global__ void R_D_CUT(const int n, Dtype* r, Dtype* d
        , Dtype cur_r_max, Dtype cur_r_min, Dtype cur_d_max, Dtype cur_d_min) {
        CUDA_KERNEL_LOOP(index, n) {

            r[index] = std::min<Dtype>(cur_r_max, std::max<Dtype>(r[index], cur_r_min));
            d[index] = std::min<Dtype>(cur_d_max, std::max<Dtype>(d[index], cur_d_min));
        }
    }

However, when I recompile, I got the error

_layer.cu(7): error: calling a __host__ function("std::min<float> ") from a __global__ function("caffe::R_D_CUT<float> ") is not allowed

_layer.cu(7): error: calling a __host__ function("std::max<float> ") from a __global__ function("caffe::R_D_CUT<float> ") is not allowed

_layer_layer.cu(8): error: calling a __host__ function("std::min<float> ") from a __global__ function("caffe::R_D_CUT<float> ") is not allowed

_layer_layer.cu(8): error: calling a __host__ function("std::max<float> ") from a __global__ function("caffe::R_D_CUT<float> ") is not allowed

_layer_layer.cu(7): error: calling a __host__ function("std::min<double> ") from a __global__ function("caffe::R_D_CUT<double> ") is not allowed

_layer_layer.cu(7): error: calling a __host__ function("std::max<double> ") from a __global__ function("caffe::R_D_CUT<double> ") is not allowed

_layer_layer.cu(8): error: calling a __host__ function("std::min<double> ") from a __global__ function("caffe::R_D_CUT<double> ") is not allowed

_layer_layer.cu(8): error: calling a __host__ function("std::max<double> ") from a __global__ function("caffe::R_D_CUT<double> ") is not allowed

Could you help me to fix it? Thanks

Upvotes: 4

Views: 3451

Answers (2)

einpoklum
einpoklum

Reputation: 131646

Adding to @RobertCrovella's answer: If you want something which behaves more like std::max, you can use this templated wrapper over CUDA's math library:

#define __df__ __device__ __forceinline__
template <typename T> __df__ T maximum(T x, T y);
template <> __df__ int                 maximum<int               >(int x, int y)                               { return max(x,y);    }
template <> __df__ unsigned int        maximum<unsigned          >(unsigned int x, unsigned int y)             { return umax(x,y);   }
template <> __df__ long                maximum<long              >(long x, long y)                             { return llmax(x,y);  }
template <> __df__ unsigned long       maximum<unsigned long     >(unsigned long x, unsigned long y)           { return ullmax(x,y); }
template <> __df__ long long           maximum<long long         >(long long x, long long y)                   { return llmax(x,y);  }
template <> __df__ unsigned long long  maximum<unsigned long long>(unsigned long long x, unsigned long long y) { return ullmax(x,y); }
template <> __df__ float               maximum<float             >(float x, float y)                           { return fmaxf(x,y);  }
template <> __df__ double              maximum<double            >(double x, double y)                         { return fmax(x,y);   }
#undef __df__

(see here for a more complete set of these wrappers.)

Upvotes: 2

Robert Crovella
Robert Crovella

Reputation: 151944

Generally speaking, functionality associated with std:: is not available in CUDA device code (__global__ or __device__ functions).

Instead, for many math functions, NVIDIA provides a CUDA math library.

For this case, as @njuffa points out, CUDA provides templated/overloaded versions of min and max. So you should just be able to use min() or max() in device code, assuming the type usage corresponds to one of the available templated/overloaded types. Also, you should:

#include <math.h>

Here is a simple worked example showing usage of min() for both float and double type:

$ cat t381.cu
#include <math.h>
#include <stdio.h>

template <typename T>
__global__ void mymin(T d1, T d2){

  printf("min is :%f\n", min(d1,d2));
}


int main(){

  mymin<<<1,1>>>(1.0, 2.0);
  mymin<<<1,1>>>(3.0f, 4.0f);
  cudaDeviceSynchronize();
}
$ nvcc -arch=sm_52 -o t381 t381.cu
$ ./t381
min is :1.000000
min is :3.000000
$

Note that the available overloaded options even include some integer types

Upvotes: 8

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