CODEWITHSUNDEEP
arraysbash
user3925467
user3925467

Reputation: 53

Saving part of each line to an array in bash

I am trying to read from a file that is storing user names and addresses in the format of name:address on each new line and I wish to store only the addresses into an array. Is there any way to do this? My code currently looks like this:

while IFS=: read -r username address; do
   array=${address}
done <userfile.txt

Which is only storing the address from the first line in the file and stopping.

Upvotes: 2

Views: 45

Answers (2)

Inian
Inian

Reputation: 85895

You are almost right! You just need to append to the array using the += operator (append) which bash arrays provide. 

declare -a myArray=()
while IFS=: read -r username address; do
   myArray+=("$address")
done < userfile.txt

Doing the above should do the trick for you. Note that the parentheses are also critical here. array+=(something) appends a new element to the array, while array+=something just appends text to the first element of the array. Optionally later to print the array contents each in separate line use printf as

printf "%s\n" "${myArray[@]}"

Upvotes: 2

MrCryo
MrCryo

Reputation: 681

You can use array+=($address) form of adding array element.

array=()
while IFS=: read -r username address; do
   array+=("$address")
done < userfile.txt 
echo ${array[@]}

Upvotes: 2

Related Questions