CODEWITHSUNDEEP
pythonregex
Tristan Forward
Tristan Forward

Reputation: 3524

REGEX Remove from end of string

I have the following string:

x = r"""<FNT size='9'>" & [FacilityID] & " " & [DIAMETER] & "</FNT>"""

Trying dynamically using regular expressions or similar to get final result of :

[FacilityID] & " " & [DIAMETER]

Cannot hardcore the end result.

I have this to remove the from of string up to first [

b = re.sub(r'^.*?\&\s', '', x)

But I can't figure out how to do the reverse to the first ] reading from right to left.

I think i need to use the $ sign but I can't get it to work, thanks

Upvotes: 1

Views: 173

Answers (3)

Jan
Jan

Reputation: 43199

You could use

\[.+\]
# match [, anything else, backtrack to the first ] found

Instead of removing everything, you could simply extract the desired output.

In Python:

import re

string = """
<FNT size='9'>" & [FacilityID] & " " & [DIAMETER] & "</FNT>
<FNT size='9'>" & [anything else] & " " & [something here] & "</FNT>
"""

rx = re.compile(r'\[.+\]')

matches = [match.group(0) for match in rx.finditer(string)]
print(matches)
# ['[FacilityID] & " " & [DIAMETER]', '[anything else] & " " & [something here]']

See a demo on regex101.com.

Upvotes: 0

hyperneutrino
hyperneutrino

Reputation: 5425

If you really just want the first [ to the last ], you don't even need a regular expression, just index and lastindex.

x = r"""<FNT size='9'>" & [FacilityID] & " " & [DIAMETER] & "</FNT>"""

open = x.find("[")
close = x.rfind("]")

print(x[open:close + 1])

Upvotes: 2

Joe Iddon
Joe Iddon

Reputation: 20434

Search for the first open square bracket and then get all characters to the next closing square bracket and then all characters to the final closing square bracket:

x = r"""<FNT size='9'>" & [FacilityID] & " " & [DIAMETER] & "</FNT>"""

x = re.findall("\[.*?\].*?\]", x)[0]

which modifies x to:

'[FacilityID] & " " & [DIAMETER]'

Upvotes: 0

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