CODEWITHSUNDEEP
pythonpython-3.x
Evan Hsueh
Evan Hsueh

Reputation: 149

Removing text from each element of a list in python

I have a list that has strings like ['\t30/30','\t10/10'] because I used regular expressions in some raw input data from a string called grades.

number = re.findall(r'\t\d{1,3}\/\d{1,3}',grades)
number[:] = [item.replace('\t', '') for item in number]

How to I remove the \t in each element of my list "number"? The second line gives me an error: 

AttributeError: 'list' object has no attribute 'replace'

Upvotes: 1

Views: 2402

Answers (3)

tobias_k
tobias_k

Reputation: 82929

I actually can not reproduce your problem. Make sure numbers is what you think it is. It seems to be list of lists instead.

>>> grades = "bla bla \t23/40 foo bar bla \t12/20"
>>> number = re.findall(r'\t\d{1,3}\/\d{1,3}',grades)
>>> [item.replace("\t", "") for item in number]
['23/40', '12/20']

Alternatively, you could use str.strip to make it a bit shorter:

>>> [item.strip() for item in number]
['23/40', '12/20']

However, I would instead suggest to use a capturing group in your regex so the \t is not even part of the result:

>>> re.findall(r'\t(\d{1,3}\/\d{1,3})',grades)
['23/40', '12/20']

Or use one group for each of the numbers, so you don't have to split them afterwards:

>>> re.findall(r'\t(\d{1,3})\/(\d{1,3})',grades)
[('23', '40'), ('12', '20')]

Upvotes: 2

DoesData
DoesData

Reputation: 7047

data = ['\t30/30', '\t10/10']
no_tabs = filter(lambda x: x != '\t', data)

print(*no_tabs)
30/30   10/10

Upvotes: 0

Ajax1234
Ajax1234

Reputation: 71461

You can try this:

import re
number = re.findall(r'\t\d{1,3}\/\d{1,3}',grades)
final_data = [re.findall('[^\t]+', i)[0] for i in number]

When running this code with number = ['\t30/30','\t10/10'], the output is:

['30/30', '10/10']

Upvotes: 1

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