Reputation: 4102
I have a returned datastructure that I want to explode into multiple rows.
For Example:
columns = ['A', 'B', 'C']
data = [1,['X','Y', 'Z'], 23]
df = pd.DataFrame(data, columns=columns)
This gives me 3 rows where one column is a list object.
I want to explode the row into 3 rows based on the column B
. To get the r esult:
A B C
1 X 23
1 Y 23
1 Z 23
Is there a built in command to do this or a method out there?
Thanks
Upvotes: 1
Views: 46
Reputation: 76917
You could use
In [114]: pd.DataFrame(dict(zip(columns, data)))
Out[114]:
A B C
0 1 X 23
1 1 Y 23
2 1 Z 23
Upvotes: 3