CODEWITHSUNDEEP
carrayshexrgbatoi
s.r.
s.r.

Reputation: 146

Get the RGB-hexadecimal values from an array and give it to an malloc-array as int

I need a method, how I can get a hexadecimal number from an array, then give it to a variable with the type int. I know that sounds easy but I need it in a "special way" - for example:

I have given a RGB hex color: 01a7ff - and I saved the value of R, G and B in extra arrays - looking like this:

char red[3];
red[0] = '0';
red[1] = '1';
red[2] = '\0';

char green[3];
green[0] = 'a';
green[1] = '7';
green[2] = '\0';

char blue[3];
blue[0] = 'f';
blue[1] = 'f';
blue[2] = '\0';

Now I want to give the complete array of red, green and blue to a malloc reserved array so it looks like this:

char *data;
data = malloc(sizeof(char)*6);

data[0] = 01; //red array
data[1] = a7; //green array
data[2] = ff; //blue array

I first tried using atoi() but that didn't work if the array had also de hexadecimal literals (a,b,c,d,e,f) - has anyone a solution for me?

Cheers

Upvotes: 0

Views: 169

Answers (1)

sg7
sg7

Reputation: 6298

Providing that data holds unsigned char values this should do: 

data[0] = (unsigned char) strtol(red, NULL, 16);
data[1] = (unsigned char) strtol(green, NULL, 16);
data[2] = (unsigned char) strtol(blue, NULL, 16);

Note: It is enough to use unsigned char to hold data value from 0 to 255

Upvotes: 1

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