CODEWITHSUNDEEP
pythonvimcall
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Reputation: 159

python call vim open multiple files

I'm trying to call vim from a python script to open multiple files.

files = []
for i in sys.argv[1:]:
    files.append(i)

string = " ".join(str(x) for x in files)
call(["vim", string])

when I call ./open.py 11 42 39 it only open one file called "11 42 39".

How to open them as separates files ?

Thank you.

Upvotes: 1

Views: 111

Answers (1)

FlyingTeller
FlyingTeller

Reputation: 20599

You need to have the seperate files as seperate items in your list:

call(["vim"] + files)

That is because when you pass a list, then each element in the list after the first one is given to vim as a seperate argument. So you are just giving vim the argument "11 42 39". The argument will not be split at " " into three seperate arguments.

If you want to see all files at the same time you can also add -o to the call to vim:

call(["vim", "-o"] + files)

Upvotes: 3

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