Reputation: 755
Simple expression:
variable x ok
4 x ! ok
3 x < . -1 ok
3 x > . 0 ok
This seems normal and correct, however:
variable x ok
3 x ! ok
x 4 < . 0 ok
x 4 > . -1 ok
The second block of code is wrong. What is evaluating wrongly? What is the problem here?
Upvotes: 1
Views: 74
Reputation: 14325
variable x
makes a new variable, but x
returns the address, not the value.
You need something like this:
variable x
3 x ! ok
x @ 4 < .
x @ 4 > .
Upvotes: 3