CODEWITHSUNDEEP
javaregex
Tarek Gaddour
Tarek Gaddour

Reputation: 43

Java regex matcher doesnt match

I cant understand why the result is always false

package test;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Test {

    public static void main(String args[]) { 
        String pattern = "place (//d+);(//d+);(//d+);(//d+)";

        // Create a Pattern object
        Pattern r = Pattern.compile(pattern);

        Matcher matcher1 = r.matcher("place 66;33;65;87");

        System.out.println(matcher1.matches());

    }

}

Upvotes: 0

Views: 258

Answers (2)

Andrey Tyukin
Andrey Tyukin

Reputation: 44992

The escaping character in both regex and java String literals is a backslash, not a forward slash. You want to get \d in regex (escaped d for digits). You have to escape it by another backslash in string literal, so you obtain \\d.

With

"place (\\d+);(\\d+);(\\d+);(\\d+)"

it matches and works.

You can of course take it sportive and try to write a regex-replacement that replaces all // by \ in your regex... Something like this:

String pattern = "place (//d+);(//d+);(//d+);(//d+)".replaceAll("//", "\\\\");

Upvotes: 1

CodeHunter
CodeHunter

Reputation: 2082

This would work:

public static void main(String args[]) {
        String pattern = "(place) (\\d+);(\\d+);(\\d+);(\\d+)";

        // Create a Pattern object
        Pattern r = Pattern.compile(pattern);

        Matcher matcher1 = r.matcher("place 66;33;65;87");

        System.out.println(matcher1.matches());
    }

You need to provide place in round braces and the slash thing.

Upvotes: 0

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