Reputation: 11
trait BT {
fn get_a(&self) -> &A;
}
#[derive(Debug)]
struct A {
v: i32,
}
impl A {
fn nb(&self) -> Box<BT> {
Box::new(B { a: self })
}
}
#[derive(Debug)]
struct B<'a> {
a: &'a A,
}
impl<'a> BT for B<'a> {
fn get_a(&self) -> &A {
return self.a;
}
}
fn main() {
println!("{:?}", A { v: 32 }.nb().get_a());
}
A
has a method to generate a B
instance with a reference of A
, and B
might have many methods access B.a
(A's reference in B). If let A.nb()
return B
instead of BT
, the code would work well.
I'm new to Rust. This problem has troubled me all day. What should I do to make this code work? Thanks!
The whole error report:
error[E0495]: cannot infer an appropriate lifetime for lifetime parameter `'a` due to conflicting requirements
--> src\socket\msg\message.rs:53:26
|
53 | Box::new(B{a: self})
| ^
|
note: first, the lifetime cannot outlive the anonymous lifetime #1 defined on the method body at 52:13...
--> src\socket\msg\message.rs:52:13
|
52 | / fn nb(&self) -> Box<BT> {
53 | | Box::new(B{a: self})
54 | | }
| |_____________^
note: ...so that reference does not outlive borrowed content
--> src\socket\msg\message.rs:53:31
|
53 | Box::new(B{a: self})
| ^^^^
= note: but, the lifetime must be valid for the static lifetime...
= note: ...so that the expression is assignable:
expected std::boxed::Box<socket::msg::message::test::test::BT + 'static>
found std::boxed::Box<socket::msg::message::test::test::BT>
Upvotes: 1
Views: 119
Reputation: 5216
The default lifetime of a trait object is 'static
. You need to add an explicit lifetime bound to the trait object returned by nb()
function:
impl A {
fn nb<'s>(&'s self) -> Box<BT+'s> {
Box::new(B{a: self})
}
}
Inference of Trait Object Lifetimes
Upvotes: 3