CODEWITHSUNDEEP
linuxbash
VintageKoala
VintageKoala

Reputation: 1

I'm trying to grep folders and make a variable of the result for further need

GET_DIR=$ (find ${FIND_ROOT} -type -d 2>/dev/null | grep -Eiv ${EX_PATTERN| grep -Eio ${FIND_PATTERN})

but somehow when I try to print the result, its empty. But when I am using my grep without a script I got results on the Command line.

Upvotes: 0

Views: 42

Answers (2)

Shreya Singh
Shreya Singh

Reputation: 1

consider using xargs :

GET_DIR=$ (find ${FIND_ROOT} -type -d 2>/dev/null | xargs grep -Eiv ${EX_PATTERN| grep -Eio ${FIND_PATTERN})

Upvotes: 0

nbari
nbari

Reputation: 27005

You could avoid the pipe | and grep by using name or iname (case insensitive) within find, for example:

find /tmp -type d -iname "*foo*"

This will find directories -type d that match the pattern *foo* ignoring case -iname in /tmp

To save the output in a variable you could use:

FOO=$(find /tmp -type d -iname "*foo*")

From the find man:

 -name pattern
         True if the last component of the pathname being examined matches pattern.  Special shell pattern matching
         characters (``['', ``]'', ``*'', and ``?'') may be used as part of pattern.  These characters may be matched
         explicitly by escaping them with a backslash (``\'').

Upvotes: 1

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