CODEWITHSUNDEEP
bashdirectorygrep
Rgonomike
Rgonomike

Reputation: 338

Bash scripting: List of folders in a variable and grep the exact directory name

Here is my problem. To get a list of directory where the file GC.xml is:

EXBRANDS=find /var/www/html/ -maxdepth 3 -name "GC.xml" -type f | awk -F '/' '{print $5}';

#echo $EXBRANDS

#dir1 dir2 dir3 (it appears exactly like this)

#read var

Enter "dir" for example

That's where I'm having trouble to identify the exact pattern I typed to compare it against my directory list.

echo $EXBRANDS | grep "[ $var]\|[$var ]\|[ $var]" if [[ $? -eq 0 ]] ; then ..... else ..... fi;

I think there is a problem with my grep command as if I pass the value "dir" to $var my grep command actually finds the directory and returns $?=0

My wish is to get $?=0 only if it finds exactly the pattern $var in my grep command...

What are the best grep (egrep) options here? Or is my method completely stupid?

Upvotes: 1

Views: 1373

Answers (2)

guido
guido

Reputation: 19224

Try using word boundaries:

if [ ! -z "$var" ] ;  
    then echo $EXBRANDS | grep -e "\b$var\b"; 
    if [[ $? -eq 0 ]] ; 
        then echo "Y"; 
        else echo "N"; 
    fi;
    else echo "input dir must be not null"; 
fi;

EDIT: add null check

Upvotes: 1

jfg956
jfg956

Reputation: 16768

Your EXBRANDS contains many lines, and you loose these lines with echo.

I would do that the other way:

read var
find /var/www/html/ -maxdepth 3 -name "GC.xml" -type f | awk -F '/' '{print $5}' | grep "^$var\$"
if [[ $? -eq 0 ]] ; then ...  else ... fi;

Be sure that the grep match an exact line with the "^$var\$" construct.

Edit: you could also printf "$EXBRANDS" | grep "^$var\$" instead of echo, it might solve your problem.

Upvotes: 2

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