Reputation: 27
I have 3 4x4 arrays (matrices) created with: arr=np.linspace(1,48,48).reshape(3,4,4)
The matrices appear as below: `
[[[ 1. 2. 3. 4.]
[ 5. 6. 7. 8.]
[ 9. 10. 11. 12.]
[13. 14. 15. 16.]]
[[17. 18. 19. 20.]
[21. 22. 23. 24.]
[25. 26. 27. 28.]
[29. 30. 31. 32.]]
[[33. 34. 35. 36.]
[37. 38. 39. 40.]
[41. 42. 43. 44.]
[45. 46. 47. 48.]]]`
I would like to perform indexing/splicing to obtain certain outputs eg:
[[36. 35.] [40. 39.] [44. 43.] [48. 47.]]
[[13. 9. 5. 1.] [29. 25. 21. 17.] [45. 41. 37. 33.]]
[[25. 26. 27. 28.], [29. 30. 31. 32.], [33. 34. 35. 36.], [37. 38. 39. 40.]]
4*. [[1. 4.] [45. 48.]]
I am struggling with exactly how to approach it. When working with a particular matrix, I have attempted to access that matrix and then splice/index from there. For example, the output [[36. 35.] [40. 39.] [44. 43.] [48. 47.]] lies in the third matrix. I access the matrix like this matrix3 = arr[array([2])]
Now I am only working with rows and columns in the third matrix and am finding it difficult to slice correctly. Should matrix3[::-1,::-1]
invert both columns and rows? If yes then is this the best way to approach it? Instead, should I use reshape and should you use reshape on all 3 4x4 arrays or access the matrix you want to work with and then reshape?
edit: added 4.
Upvotes: 0
Views: 215
Reputation: 231665
Extracting your first result, step by step:
In [53]: arr[2,:,:] # the desired plane
Out[53]:
array([[33, 34, 35, 36],
[37, 38, 39, 40],
[41, 42, 43, 44],
[45, 46, 47, 48]])
In [54]: arr[2,:,2:] # the desired columns
Out[54]:
array([[35, 36],
[39, 40],
[43, 44],
[47, 48]])
In [55]: arr[2,:,:1:-1] # the reversed order
Out[55]:
array([[36, 35],
[40, 39],
[44, 43],
[48, 47]])
or if it's easier, reverse as a separate step:
In [56]: arr[2,:,2:][:,::-1]
Out[56]:
array([[36, 35],
[40, 39],
[44, 43],
[48, 47]])
In [57]: arr[:,:,0] # select column
Out[57]:
array([[ 1, 5, 9, 13],
[17, 21, 25, 29],
[33, 37, 41, 45]])
In [58]: arr[:,::-1,0] # reverse
Out[58]:
array([[13, 9, 5, 1],
[29, 25, 21, 17],
[45, 41, 37, 33]])
In [59]: arr[:,::-1,0].T # transpose
Out[59]:
array([[13, 29, 45],
[ 9, 25, 41],
[ 5, 21, 37],
[ 1, 17, 33]])
This is a little trickier. We want last 2 rows for one plane, and first two for another plane. To get that we need a pair on indices that will broadcast to the correct shape, pairing up 1
with [2,3]
etc.
In [61]: arr[[[1],[2]],[[2,3],[0,1]],:]
Out[61]:
array([[[25, 26, 27, 28],
[29, 30, 31, 32]],
[[33, 34, 35, 36],
[37, 38, 39, 40]]])
This is a 3d matrix; one way to reduce it to 2d is to concatenate:
In [63]: np.concatenate(arr[[[1],[2]],[[2,3],[0,1]],:],axis=0)
Out[63]:
array([[25, 26, 27, 28],
[29, 30, 31, 32],
[33, 34, 35, 36],
[37, 38, 39, 40]])
reshape works just as well:
In [65]: arr[[[1],[2]],[[2,3],[0,1]],:].reshape(4,4)
Out[65]:
array([[25, 26, 27, 28],
[29, 30, 31, 32],
[33, 34, 35, 36],
[37, 38, 39, 40]])
Also arr.reshape(3,2,2,4)[[1,2],[1,0],:].reshape(4,4)
You can write these indexing expressions as tuples with slices, e.g.:
In [66]: idx = (2, slice(None), slice(None,1,-1))
In [67]: arr[idx]
Out[67]:
array([[36, 35],
[40, 39],
[44, 43],
[48, 47]])
So in general the common tools include indexing (with slices, scalars and lists), reversing (-1 step), transposing (or swapaxes), and reshaping. You can't do everything with just one of these.
Upvotes: 2
Reputation: 1103
You're on the right track with the slicing! For your desired outputs try:
arr[2,:,:1:-1]
np.vstack((arr[i, ::-1, 0] for i in range(3)))
np.vstack((arr[1, 2:, :], arr[2, :2, :]))
Output:
array([[36., 35.],
[40., 39.],
[44., 43.],
[48., 47.]])
array([[13., 9., 5., 1.],
[29., 25., 21., 17.],
[45., 41., 37., 33.]])
array([[25., 26., 27., 28.],
[29., 30., 31., 32.],
[33., 34., 35., 36.],
[37., 38., 39., 40.]])
Upvotes: 0