CODEWITHSUNDEEP
javaandroidstringparsing
Maki Tamayo
Maki Tamayo

Reputation: 35

String Substring intentionally remove character 0

Im currently working on a String parsing function and suddenly i found this problem. For example:

String data = "1234567890JOHN F DOE";

String ID = data.substring(0,9);
String Name = data.substring(10, 19);

the expected output I want for ID is "1234567890" however the only characters I got is only "123456789" and "0" is removed.

Are there any function I can use instead of substring(...)?

Upvotes: 2

Views: 115

Answers (4)

Abdo Bmz
Abdo Bmz

Reputation: 641

Let's understand the startIndex and endIndex you need to do this by the code : 

String data = "1234567890JOHN F DOE";
String ID = data.substring(0,10);
String Name = data.substring(10, 20);
    System.out.println("ID:" + ID);
    System.out.println("Name: "+  Name);

Output:

ID: 1234567890

Name: JOHN F DOE

Upvotes: 0

GBlodgett
GBlodgett

Reputation: 12819

As said in the docs the substring(...)'s ending index is the index inputted minus one. What you want to do is have: 

String data = "1234567890JOHN F DOE";
String ID = data.substring(0,10); 
String Name = data.substring(10, 20);

Output:

ID: 1234567890

Name: JOHN F DOE

Upvotes: 3

Haraden
Haraden

Reputation: 31

you get "123456789" because the end parameter in the substring(...) method is not inclusive, so in order to get "1234567890" you need to use data.substring(0,10) :)

Upvotes: 3

Adya
Adya

Reputation: 1112

Using substring you can simply do : str.substring (0,10); This is another way :

 String pattern="\\d+";
    String text="1234567890JOHN F DOE";
    Pattern p=Pattern.compile(pattern);
    Matcher m=p.matcher(text);
    while (m.find()) {
        System.out.println(text.substring(m.start(), m.end()));
    }

Upvotes: 0

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