CODEWITHSUNDEEP
c#urluwpstoragefolder
Asem Khen
Asem Khen

Reputation: 363

How to convert an Image URL into a StorageFile?

I am working with Unsplash API to get Images. When I send the request for an Image, part of the answer is the Image URL which looks like this:

https://images.unsplash.com/photo-1535159530326-d7bf54bfb24e?ixlib=rb-0.3.5&q=85&fm=jpg&crop=entropy&cs=srgb&ixid=eyJhcHBfaWQiOjM1NDkzfQ&s

I was able to make this URL a BitmapImage and make it an Image Source in the app UI. But I was not able to download it to make it a StorageFile.

How can I download the image from this kind of URL and/or make it a StorageFile?

Upvotes: 2

Views: 453

Answers (1)

Greg Thatcher
Greg Thatcher

Reputation: 1453

The following code will download the file into local storage, and then give you a Uri that you can use to set the Image Source:

    private async Task<String> DownloadImage(string url, String fileName)
    {
        const String imagesSubdirectory = "DownloadedImages";
        var rootFolder = await ApplicationData.Current.LocalFolder.CreateFolderAsync(imagesSubdirectory, CreationCollisionOption.OpenIfExists);

        var storageFile = await rootFolder.CreateFileAsync(fileName, CreationCollisionOption.ReplaceExisting);

        using (HttpClient client = new HttpClient())
        {
            byte[] buffer = await client.GetByteArrayAsync(url);
            using (Stream stream = await storageFile.OpenStreamForWriteAsync())
                stream.Write(buffer, 0, buffer.Length);
        }

        // Use this path to load image
        String newPath = String.Format("ms-appdata:///local/{0}/{1}", imagesSubdirectory, fileName);

        return newPath;
    }

    // Here is an example of how to use the new DownloadImage() method
    private async void Button_Download(object sender, RoutedEventArgs e)
    {
        var uniqueFileName = $@"{Guid.NewGuid()}.jpg";

        String newPath = await DownloadImage("https://images.unsplash.com/photo-1535159530326-d7bf54bfb24e?ixlib=rb-0.3.5&q=85&fm=jpg&crop=entropy&cs=srgb&ixid=eyJhcHBfaWQiOjM1NDkzfQ&s=6dbf8e03a25f469d0f845992e6b2eb9e",
            uniqueFileName);
        myImage.Source = new BitmapImage(new Uri(newPath));
    }

Upvotes: 3

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