CODEWITHSUNDEEP
javascriptecmascript-6
Vincent Hoch-Drei
Vincent Hoch-Drei

Reputation: 661

Default destructed function parameters in one object in JavaScript

is there a possibility to access ALL destructed function parameters in one object?

So I have this function head:

function coolFunctionName({test1 = "foo", test2 = "bar"})

I want to access them in one object. arguments doesn't work, because there aren't stored the default parameters which doesn't have a value in function call.

Is there a good and clean way to do that?

EDIT: I don't need the destructed parameters. I just want to have all of them in one object.

Upvotes: 1

Views: 184

Answers (3)

Naga Sai A
Naga Sai A

Reputation: 10975

To achieve expected result, use below option of setting default value inside function

function coolFunctionName(x){
  x.test1 = x.test1 || 'foo'
  x.test2 = x.test2 || 'bar'
  console.log(x)
}
let z ={}
coolFunctionName(z);
let y ={test1:"zzz", test2:"yyy"}
coolFunctionName(y);

codepen- https://codepen.io/nagasai/pen/KxBmod?editors=1011

Upvotes: 0

Vincent Hoch-Drei
Vincent Hoch-Drei

Reputation: 661

Inspired from Faly's answer I think I've got the "cleanest" solution: 

function coolFunctionName(options = {}){
    options = Object.assign({
        test1: "foo",
        test2: "bar
    }, options);
}

I have the parameter in one object and I have not to write multiple value names. I'm not happy about that because it's not in the function head but it's the best solution I've found.

Upvotes: 2

Faly
Faly

Reputation: 13346

All you can do is:

function coolFunctionName({test1 = "foo", test2 = "bar"}) {
    let arguments = { test1, test2 };
    /* Do whatever you want with arguments */
}

Upvotes: -1

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