Reputation: 93
I have rows:
PLACE DATE_OPEN SUM
-----------------------
PLACE1 03.09.2018 2
PLACE2 03.09.2018 2
PLACE1 04.09.2018 8
PLACE1 05.09.2018 9
PLACE2 05.09.2018 1
I get the rows using this SQL query:
SELECT
SB AS [PLACE],
CAST(OPEN_TIME AS DATE) AS [DATE_OPEN],
COUNT(ID) AS [SUM]
FROM
[Table]
WHERE
SB IN ('PLACE1', 'PLACE2')
GROUP BY
SB, CAST(OPEN_TIME AS DATE)
I want to get a table in the form of a summary table, is it possible to do this using SQL?
Example of the desired output:
PLACE DATE_OPEN
03.09.2018 04.09.2018 05.09.2018
PLACE1 2 8 9
PLACE2 2 1
Upvotes: 0
Views: 960
Reputation: 9143
The closest is PIVOT:
WITH Demo AS
(
SELECT * FROM (VALUES
('PLACE1', '03.09.2018', 2),
('PLACE2', '03.09.2018', 2),
('PLACE1', '04.09.2018', 8),
('PLACE1', '05.09.2018', 9),
('PLACE2', '05.09.2018', 1)) T(PLACE, DATE_OPEN, [SUM])
)
SELECT * FROM Demo
PIVOT (SUM([Sum]) FOR Date_Open IN ([03.09.2018],[04.09.2018],[05.09.2018])) P
Result
PLACE 03.09.2018 04.09.2018 05.09.2018
------ ----------- ----------- -----------
PLACE1 2 8 9
PLACE2 2 NULL 1
Upvotes: 1