CODEWITHSUNDEEP
pythonpython-3.x
Jamie McClenaghan
Jamie McClenaghan

Reputation: 49

How to correctly check through an array

Here is my code

def gen_code(codeLength):
    symbols = ('ABCDEF')
    code = random.sample(symbols, k=codeLength)
    return str(code)

def print_code(code):
    i = 0
    while i < len(code):
        print(code[i])
        i += 1

code = gen_code(codeLength)
print("The code is " + code)
convCode = code[0] + code[1] + code[2] + code[3]
print(convCode)

So I basically want to generate a random string from the letters I have provided and then check if the user guesses a correct entry in that string (I'm trying to make mastermind). The issue I have is checking to see if the user's guess is in the code which is generated.

This is what my code outputs: Output

Why is my convCode variable printing ['E' and not EAFB?

Upvotes: 0

Views: 54

Answers (3)

mad_
mad_

Reputation: 8273

code is a list use slicing to get the required result which will give you flexibility as you need not write hardcoded list indices each time.

import random
def gen_code(codeLength):
    symbols = ('ABCDEF')
    code = random.sample(symbols, k=codeLength)
    return code

def print_code(code):

    i = 0
    while i < len(code):
        print(code[i])
        i += 1

code = gen_code(5)
print("The code is " + str(code))
convCode =code[:4]
print(convCode)

Upvotes: 0

Uvar
Uvar

Reputation: 3462

If the code is returned as a list instead of a string, you can access the individual letters of the code in the manner you want to.

import random
codeLength=4
def gen_code(codeLength):
    symbols = ('ABCDEF')
    code = random.sample(symbols, k=codeLength)
    return code
def print_code(code):
    i = 0
    while i < len(code):
        print(code[i])
        i += 1

code = gen_code(codeLength)
print("The code is " + str(code))
convCode = code[0] + code[1] + code[2] + code[3]
print(convCode)

Upvotes: 1

killian95
killian95

Reputation: 813

In your gen_code function you convert the list to a string before you return it:

def gen_code(codeLength):
    symbols = ('ABCDEF')
    code = random.sample(symbols, k=codeLength)

    # This converts it to a string, rather than leaving it as a list
    # which is presumably what you want.
    return str(code)

So later in your code:

convCode = code[0] + code[1] + code[2] + code[3]

Gives you the first four characters of that string which are exactly ['E'

Try changing gen_code to this:

def gen_code(codeLength):
    symbols = ('ABCDEF')
    code = random.sample(symbols, k=codeLength)
    return code

Upvotes: 0

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