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I am a Coder

Reputation: 33

Decode alfresco file name or replace unicode[_x0020_] characters in String/fileName

I am using alfresco download upload services using java.

When I upload the file to alfreco server it gives me the following path :

/app:Home/cm:Company_x0020_Home/cm:Abc/cm:TestFile/cm:V4/cm:BC1X_x0020_0400_x0020_0109-_x0028_1-2_x0029__v2.pdf

When I use the same file path and download using alfresco services I took the file name at the end of the path 

i.e    ABC1X_x0020_0400_x0020_0109-_x0028_1-2_x0029__v2.pdf

How can I remove or decode the [Unicode] characters in fileName

String decoded = URLDecoder.decode(queryString, "UTF-8");

The above does not work .

These are some Unicode characters which appeared in my file name. https://en.wikipedia.org/wiki/List_of_Unicode_characters

Please do not mark the question as duplicate as I have searched below links but non of those gave the solution. Following are the links that I have searched for replacing unicode charectors in String with java.

Java removing unicode characters

Remove non-ASCII characters from String in Java

How can I replace a unicode character in java string

Java Replace Unicode Characters in a String

Upvotes: 3

Views: 1406

Answers (2)

KishanCS
KishanCS

Reputation: 1377

The solution given by Jeff Potts will be perfect . But i had a situation where i was using file name in diffrent project where i wont use org.alfresco related jars

I had to take all those dependencies to use for a simple file decoding So i used java native methods which uses regex to parse the file name and decode it,which gave me the perfect solution which was same from using 

ISO9075.decode(test);

This is the code which can be used 

 public String decode_FileName(String fileName) {
        System.out.println("fileName : " + fileName);
        String decodedfileName = fileName;
        String temp = "";
        Matcher m = Pattern.compile("\\_x(.*?)\\_").matcher(decodedfileName); //rejex which matches _x0020_ kind of charectors
        List<String> unicodeChars = new ArrayList<String>();
        while (m.find()) {
            unicodeChars.add(m.group(1));
        }
        for (int i = 0; i < unicodeChars.size(); i++) {
            temp = unicodeChars.get(i);
            if (isInteger(temp)) {
                String replace_char = String.valueOf(((char) Integer.parseInt(String.valueOf(temp), 16)));//converting  
                decodedfileName = decodedfileName.replace("_x" + temp + "_", replace_char);
            }
        }
        System.out.println("Decoded FileName :" + decodedfileName);
        return decodedfileName;
    }

And use this small java util to know Is integer

public static boolean isInteger(String s) {
        try {
            Integer.parseInt(s);
        } catch (NumberFormatException e) {
            return false;
        } catch (NullPointerException e) {
            return false;
        }
        return true;
    }

So the above code works as simple as this :

Example :

0028 Left parenthesis U+0028 You can see in the link https://en.wikipedia.org/wiki/List_of_Unicode_characters

String replace_char = String.valueOf(((char) Integer.parseInt(String.valueOf("0028"), 16)));
        System.out.println(replace_char);

This code gives output : ( which is a Left parenthesis

This is what the logic i have used in my java program.

The above program will give results same as ISO9075.decode(test)

Output :

fileName : ABC1X_x0020_0400_x0020_0109-_x0028_1-2_x0029__v2.pdf
Decoded FileName :ABC1X 0400 0109-(1-2)_v2.pdf

Upvotes: 3

Jeff Potts
Jeff Potts

Reputation: 10538

In the org.alfresco.util package you will find a class called ISO9075. You can use it to encode and decode strings according to that spec. For example:

    String test = "ABC1X_x0020_0400_x0020_0109-_x0028_1-2_x0029__v2.pdf";
    String out = ISO9075.decode(test);
    System.out.println(out);

Returns:

    ABC1X 0400 0109-(1-2)_v2.pdf

If you want to see what it does behind the scenes, look at the source.

Upvotes: 2

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