Solve() and Assume() in Maxima

Question

I'm trying to solve a trigonometric function assuming positive values of the independent variable. However seems like Maxima does not take into account such assumption for the solve routine.

assume(t >0);
solve(sin(t) = 0);

The expected result:

[t=%pi]

What I get:

[t=0]

Answer 1

One could use to_poly_solve package; see the docs.

load(to_poly_solve);
to_poly_solve(sin(t), t);

which yields

%union([t = %pi %z0])

which is the result you expect.