CODEWITHSUNDEEP
bashpowershellbatch-file
Twml
Twml

Reputation: 441

mass rename zip files to original name but removing part of name

I have directories with a lot of zips in them.

all with different names of software that have been acquired over time.

Ex: 

Software1_ABCDE-FGHIJ.zip
Software2_256SS-BM42.zip
Software3_aswdfbbgtyyn.zip

I want to use batch/powershell or bash to rename them all to

Ex: 

Software1.zip
Software2.zip
Software3.zip

Basically anything after _ and before .zip needs to go, But its all random content... Serial keys basically. The names are to long for my php downloader i made on my server, and limit is needed for other things to function so i need to rename 100s of zips.

I already have a for loop to zip all files/folders in a dir in to own zip in bash.

for i in */; do zip -r "${i%/}.zip" "$i"; done

and i already have this bash that takes .exe out of any file name before the .zip

rename.ul '.exe' '' *.zip

Ex:

file1_23434434.exe.zip

became

file1_23434434.zip

How can i mass rename all my zips from software1_serial-here-1234.zip to software1.zip

keeping original zip name of the software and the .zip extension

Upvotes: 1

Views: 681

Answers (3)

marsze
marsze

Reputation: 17055

Since you tagged your question with powershell also, this would be the PowerShell way to do it:

Get-ChildItem -Filter *.zip | Rename-Item -NewName { $_.Name -replace "_.*", ".zip" }

Short version using batch-like aliases:

dir -filter *.zip | ren -new { $_.name -replace "_.*", ".zip" }

Upvotes: 1

Mofi
Mofi

Reputation: 49086

In a Windows command prompt window run in directory containing the ZIP files:

for /F "tokens=1* delims=_ eol=" %I in ('dir *_*.zip /A-D-H /B 2^>nul') do ren "%I_%J" "%I.zip"

In a batch file stored in directory containing the ZIP files:

@for /F "tokens=1* delims=_ eol=" %%I in ('dir "%~dp0*_*.zip" /A-D-H /B 2^>nul') do ren "%~dp0%%I_%%J" "%%I.zip"

If there are multiple underscores after software name instead of just one _ or the software name starts with one or more underscores, it is necessary to use two FOR loops to rename really all *_*.zip files correct:

@for /F "delims= eol=" %%I in ('dir "%~dp0*_*.zip" /A-D-H /B 2^>nul') do @for /F "delims=_ eol=" %%J in ("%%I") do ren "%~dp0%%I" "%%J.zip"

Loop variable I of outer FOR holds complete file name of ZIP file with file extension, but without file path, and loop variable J of inner for loop holds just the file name part before first underscore. J has removed also all underscores at beginning of a file name. So __SoftwareX__Y.zip is renamed to SoftwareX.zip.

For understanding the used commands and how they work, open a command prompt window, execute there the following commands, and read entirely all help pages displayed for each command very carefully.

  • call /? ... explains %~dp0 ... drive and path of argument 0 which is the batch file path always ending with a backslash.
  • dir /?
  • for /?
  • ren /?

Upvotes: 1

Kiran Reddy
Kiran Reddy

Reputation: 2904

Get-ChildItem -Path C:\temp -Filter software* -File | 
   Rename-Item -NewName { ($_.BaseName -split '_')[0] + $_.Extension } -WhatIf

Remove the -whatif to apply the action. -whatif is for a preview.

This assumes that all files you want to rename begin with the word software and there is only one _ in the filename.

Upvotes: 0

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