CODEWITHSUNDEEP
java.util.scanner
Karthi Rasu
Karthi Rasu

Reputation: 67

How to Solve scanner class using error in Java?

I have this code input getting using Scanner Class. When ever I run this code it stores only first two values. I can't enter the third variable value.

 //Input Code
 import java.util.Scanner;
 public class Input
 {
  public static void main(String[] args)
 {
 try{
Scanner s = new Scanner(System.in);
 int i;
float f;
String str;
 System.out.println("Enter the Integer value"); //getting.   
 input from user
 i=s.nextInt();   //store the use entered value
 System.out.println("Enter the Float value");
f=s.nextFloat();
System.out.println("Enter the String value");
str=s.nextLine();
 System.out.println("\nInt: "+i+"\nFloat: "+f+"\nString 
 "+str);  //print the final result
 }
  catch(Exception e)
 {
 System.out.print(e);   
 }
 }
 }

------end------

Output:
Enter the Integer value
4
Enter the Float value
4.4
Enter the String value

Int 4
Float 4.10
String

Upvotes: 1

Views: 227

Answers (1)

Bhavesh Soni
Bhavesh Soni

Reputation: 198

Kindly change s.nextline() to s.next(). For more details, you can refer below complete code

import java.util.Scanner;

public class Input {
  public static void main(String[] args) {
    try {
      Scanner s = new Scanner(System.in);
      int i;
      float f;
      String str;
      System.out.println("Enter the Integer value"); // getting.
      // input from user
      i = s.nextInt(); // store the use entered value
      System.out.println("Enter the Float value");
      f = s.nextFloat();
      System.out.println("Enter the String value");
      str = s.next();
      System.out.println("\nInt: " + i + "\nFloat: " + f + "\nString  " + str); // print the final result
    } catch (Exception e) {
      System.out.print(e);
    }
  }
}

Upvotes: 1

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