CODEWITHSUNDEEP
azureazure-devopsazure-pipelines
Mehran Shafqat
Mehran Shafqat

Reputation: 520

Get the latest file from directory with pattern

I have a task that generate HTML reports, for example:

Api-Test-Automation-2019-06-23-12-35-54-450-0.html
Api-Test-Automation-2019-06-23-12-38-44-701-0.html

I want to get the latest report and send it in the email as attachment.

This will actually attach all files:

$(Build.SourcesDirectory)\newman\htmlreport\*.html

But I just want to add only the latest created file.

Upvotes: 0

Views: 688

Answers (1)

Shayki Abramczyk
Shayki Abramczyk

Reputation: 41735

So you have 2 HTML reports and you want to send only the last report. you can achieve this goal with a PowerShell task that set a variable with the last file path (add a PowerShell task after the html generation):

cd $(Build.SourcesDirectory)\newman\htmlreports
$files = dir -Filter *.html
$latest = $files | Sort-Object LastAccessTime -Descending | Select-Object -First 1
$lastFile = $latest.FullName
Write-Host "##vso[task.setvariable variable=latestHtml]$lastFile"

Now in the send email task just put the variable $(latestHtml).

Upvotes: 2

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