CODEWITHSUNDEEP
pythonregex
Kartik aggarwal
Kartik aggarwal

Reputation: 31

regex code for getting only the first line from the text file using python

Can anyone please provide me the regex code for printing only the first line of the data in the text file??? I am using spyder

i have tried may solutions but it prints all my data in every line ...last one helped me but it chose two lines. i just want the first line of my text file only till it encounters line break or till the text starts from next line.

import re

def getname(s):    
    nameregex=re.findall(r'^.*?[\.!\?](?:\s|$)',line)
    if len(nameregex)!=0:
        print(nameregex)


s = open('yesno.txt')     
for line in s:    
    getname(s)

In the output i am getting first two lines. Basically i am trying to print the company name only which is mostly in the first line.

Upvotes: 1

Views: 2626

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 627607

Read the file into a variable using read() and use re.search to get the match:

import re

def getname(s):    
    nameregex=re.search(r'^.*?[.!?](?!\S)', s)     # Run search with regex
    if nameregex:                                  # If there is a match 
        print(nameregex.group())                   # Get Group 0 - whole match - value


s = open('yesno.txt', 'r')                         # Open file handle to read it
contents = s.read()                                # Get all file contents
getname(contents)                                  # Run the getname method with the contents

See the Python demo.

The regex is a bit modified to avoid the whitespace at the end. See details:

  • ^ - start of the string
  • .*? - any 0 or more chars other than line break chars, as few as possible
  • [.!?] - ., ! or ? char
  • (?!\S) - there must be a whitespace or end of string here.

See the regex graph:

enter image description here

Upvotes: 1

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