one way ANOVA and TUKEY in R with conditions

Question

I am trying to find the mean differences between my variable stim_ending_t which contains the following 6 factors: 1, 1.5, 2, 2.5, 3, 3.5

You can access the df Here

stim_ending_t visbility soundvolume Opening_text               m    sd coefVar
           <dbl>     <dbl>       <dbl> <chr>                  <dbl> <dbl>   <dbl>
 1           1           0           0 Now focus on the Image  1.70 1.14    0.670
 2           1           0           0 Now focus on the Sound  1.57 0.794   0.504
 3           1           0           1 Now focus on the Image  1.55 1.09    0.701
 4           1           0           1 Now focus on the Sound  1.77 0.953   0.540
 5           1           1           0 Now focus on the Image  1.38 0.859   0.621
 6           1           1           0 Now focus on the Sound  1.59 0.706   0.444
 7           1.5         0           0 Now focus on the Image  1.86 0.718   0.387
 8           1.5         0           0 Now focus on the Sound  2.04 0.713   0.350
 9           1.5         0           1 Now focus on the Image  1.93 1.00    0.520
10           1.5         0           1 Now focus on the Sound  2.14 0.901   0.422

Here is a visual representation of my data

Q: How I can do ANOVA with the condition of comparing the mean by "Opening_test" which contains "Now focus on the Image", and "Now focus on the Sound."

Q: Also I want to follow that with post hoc test.

Here is what I have tried but apparently is not the right way!

# Compute one-way ANOVA test

res.aov <- aov(m ~ stim_ending_t, data = clean_test_master2)
summary(res.aov)

              Df Sum Sq Mean Sq F value Pr(>F)    
stim_ending_t  1  7.589   7.589   418.8 <2e-16 ***
Residuals     34  0.616   0.018                   
---
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

I think there is something wrong with result from aov! stim_ending_t has 6 factors, so Dgree of fredom (Df) should = 5 not != 1 from the above table.

# post hoc test 
TukeyHSD(res.aov, conf.level = 0.99)

Here is the message I got

Error in TukeyHSD.aov(res.aov, conf.level = 0.99) : 
  no factors in the fitted model
In addition: Warning message:
In replications(paste("~", xx), data = mf) :
  non-factors ignored: stim_ending_t

Note: the participants completed the experiment at one session by starting with either condition-Opening_text, randomly and completing the other one.

Answer 1

1. the following 6 factors: 1, 1.5, 2, 2.5, 3, 3.5

   Not! It will be one factor with six levels, if you will treat it as factor. You are using it as quantitative variable, see Df in ANOVA table. It should be 5 instead 1. Try as.factor() function before aov.

2. Is m the dependent variable? If yes, what is the visbility and soundvolume? If they are also factors, the assumption of independence is faulty. In this case you should introduce those factors to model.